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Alex73 [517]
3 years ago
5

Give three numbers whose product is about 9,000

Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0
Answer:  
________________________________________
1)   " 30, 60, 50 " .

2)  " 30, 50, 6 " .

3)  " 60, 50, 3 " . 
_______________________________________
<u>Note</u>:
_______________________________________

1)  30 * 60 * 5 = 9,000 .

2)  30 * 50 * 6 = 9,000 .

3)  60 * 50 * 3 = 9,000 . 
_______________________________________
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2 years ago
What is the best approximation of the projection of (5,-1) onto (2,6)?
Hatshy [7]

Answer:

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

Step-by-step explanation:

We have given two points  (5, -1) and (2, 6).

Let,     \vec a=5\hat {i}-\hat {j}  and  \vec b= 2\hat {i}+6\hat{j} .

and we have calculate the projection of \vec a onto \vec b.

Now,

For the calculation of projection, first we need to calculate the dot product of  \vec a  and \vec b.

\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})

     =10-6

     =4

then, we have to calculate the magnitude of \vec b.

   \mid {\vec {b}}\mid = \sqrt{2^{2}+6^{2}  } = \sqrt{40} = 2\sqrt{10}.

Now, the scalar projection of \vec a onto \vec b = \frac{\vec a.\vec b}{\mid b\mid}

                                                                 = \frac{4}{2\sqrt{10} }\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}

and the vector projection of \vec a onto \vec b = \frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b

                                                               = \frac{4}{40} . (2\hat i+ 6\hat j)

                                                                = \frac{1}{5} \hat i+\frac{3}{5} \hat j

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

                                                               

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3 years ago
How do you find the domain of a linear grap
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2 years ago
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HELP ASAP FOR BRAINLIEST: The time required to finish a test in normally distributed with a mean of 60 minutes and a standard de
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Answer:

<u>The z-score = -3.7 and p (-3.7) = 0.00011 or 0.011%</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean of time to finish a test = 60 minutes

Standard deviation of time to finish a test = 10 minutes

Time that a student finishes the test = 23 minutes

2. What is the z-score for the student?

z-score = (Time that a student finishes the test - Mean of time to finish a test)/Standard deviation of time to finish a test

Replacing with the real values:

z-score = (23 -60)/10 = -37/10 = -3.7

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4 0
3 years ago
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