Answer:
c
Step-by-step explanation:
it is non real if x²-36<0
x²<36
|x|<6
so -6<x<6
Answer:
See solution below
Step-by-step explanation:
Let the coordinate's of A and B be (1, 0) and (2,4) respectively
midpoint M (X, Y) = [(x1+x2/2, y1+y2/2)]
X = x1+x2/2
X = 1+2/2
X = 3/2
X = 1.5
Y = y1+y2/2
Y = 0+4/2
Y = 4/2
Y = 2
Hence the required midpoint (X, Y) is (1.5, 2)
Slope m = y2-y1/x2-x1
m = 4-0/2-1
m = 4/1
m = 4
Hence the slope is 4
<em>Note that the coordinates are assumed but the same calculation can be employed for any other coordinates</em>
Answer:
4.05
Step-by-step explanation:
Answer:
No
Step-by-step explanation:
Just because the derivative is 0 at a point doesn't necessarily mean it is a relative minimum or maximum. You must be able to evaluate the derivative on both sides of the point to determine if it changes signs. Since endpoints have only one side, they cannot be relative maximums or minimums.
Answer:
0.9995
Step-by-step explanation:
10% = 0.10
1 - 0.10 = 0.9
n = number of light bulbs = 7
we calculate this using binomial distribution.
p(x) = nCx × p^x(1-p)^n-x
our question says at most 4 is defective
= (7C0 × 0.1⁰ × 0.9⁷) + (7C1 × 0.1¹ × 0.9⁶) + (7C2 × 0.1² × 0.9⁵) + (7C3 × 0.1³ × 0.9⁴) + (7C4 × 0.1⁴ × 0.9³)
= 0.478 + 0.372 + 0.1239 + 0.023 + 0.0026
= 0.9995
we have 0.9995 probability that at most 4 light bulbs are defective.
