Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Answer:
7
Step-by-step explanation:
Substitution then simplify
Answer:
<h3>4.008</h3><h3 /><h3>10.1</h3>
Step-by-step explanation:
<h2>I hope it will help you</h2><h2>please make me brainlest</h2>
<h2><u>THANK</u><u> U</u></h2>
Answer:
Step-by-step explanation:
To the nearest thousand the answer is 0.
If you meant thousandth then the second 4 to the right of the decimal point occupies the thousandth place. so that 4 is followed by a 3, that 4 is not changed.
The answer is 44.544
but it does depend on what you meant.
