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3 years ago

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13 Use the replacement set {4, 6, 12} to find which values will make the equation 2x + 4 = 16 Strue. A None of the values are a

solution. B. The equation has a solution for x = 6. C. The equation has a solution for x = 12. D. The equation has a solution for x = 4.

1 answer:

storchak [24]3 years ago

3 0

I think it has to be A

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The function f(x) = x^2 is reflected across the x-axis and a stretch factor of 4 is applied to create a second function, g(x). W

Anon25 [30]

C. The vertexes are the same. The functions' vertex (h,k) values were not altered, just a (stretch/compress).

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3 years ago

What is the slope of the line whose equation is y−4= StartFraction 5 Over 2 EndFraction.(x−2)? A coordinate plane with a line pa

Katarina [22]

The slope of the given line is 5/2.

<h3>How to get the slope of the line?</h3>

The general linear equation can be written in the slope-intercept form as:

y = a*x + b

where a is the slope.

Here we have the equation:

y - 4 = (5/2)*(x - 2)

If we isolate y and expand the product in the right, we get:

y = (5/2)*(x - 2) + 4

y = (5/2)*x - (5/2)*2 + 4

y = (5/2)*x - 5 + 4

y = (5/2)*x - 1

This is the linear equation in the slope-intercept form, as you can see, the slope is equal to 5/2.

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2 years ago

McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine

jonny [76]

Answer:

$t _{critical} = 1.760$

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

$H_o: \mu_1 - \mu_2 = 0$

Alternative hypothesis;

$H_a : \mu_1 - \mu_2 > 0\\$

The pooled variance t-Test would have been determined if the population variance are the same.

$S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}$

$S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}$

$S_p^2 = 7.14$

The t-test statistics can be computed as:

$t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}$

$t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}$

$t= \dfrac{3}{1.336}$

t = 2.2450

Degree of freedom $df = (n_1 -1) + ( n_2 +1 )$

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

$t _{critical} = 1.760$

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject $H_o$ and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

$r^2 = \dfrac{t^2}{t^2 + df}$

$r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}$

$r^2 = \dfrac{5.040025}{5.040025+ 14}$

$r^2 = 0.2647$

7 0

3 years ago

The formula is T = L/S, where T is the time in seconds, L is the length of the tape in inches, and S is the operating speed in i

sashaice [31]

Answer:

Step-by-step explanation:

3 min(60 s/min) = L in / 7.5 in/s

L = 3(60)(7.5) = 1350 inches

6 0

3 years ago

One month Tammy rented

marissa [1.9K]

$3x + 2y = 20$
$8x + 4y = 45$
$where x = # of movies$ and $y = # of video games$

In order to solve this systems of equations problem, you need to use the elimination method.

You can multiply the top equation, <span> $3x + 2y = 20$ , by -2 in order to eliminate the $y$ values.

</span> $(3x + 2y = 20) *-2$ will turn into <span> $-6x - 4y = -40$
</span>
From there, we can eliminate.

<span> $-6x - 4y = -40$
</span><span> $8x + 4y = 45$
</span>
Since $4y$ and $-4y$ are opposites in sign and equal in coefficients, we can remove them from our equations and add the rest of the terms together.

<span> $-6x - 4y = -40$
</span><span> $8x + 4y = 45$
</span>will turn into -->
<span> $2x = 5$
</span>
So, x = $\frac{5}{2}$ , which means 1 movie costs $2.50. Then, we can solve for the video game price, $y$ , by substituting our x back into one of the equations.

<span> $3x + 2y = 20$
</span> $3*\frac{5}{2} + 2y = 20$
$y = \frac{25}{4}$

Each movie costs $2.50 and each video game costs $6.25.

4 0

3 years ago