Answer:
The radius of the circle is 10.2 units
Step-by-step explanation:
<u><em>The complete question is</em></u>
In the figure to the right, if AC=19 and BC=16, what is the radius?
A circle has center A. Points B and D are on the circle, with B on the left and D near the bottom. Point C lies outside the circle such that the line segment A C passes through point D and the line segments A B and B C form a right angle.
The radius is approximately (Round to the nearest tenth as needed.)
The picture of the question in the attached figure
we know that
In the right triangle ABC
Applying the Pythagorean Theorem

substitute the given values

solve for AB


Remember that the radius is the same that the segment AB
therefore
The radius of the circle is 10.2 units
Answer:
x = ±20
Step-by-step explanation:
Step 1: Write equation
x² = 400
Step 2: Square root both sides
x = ±√400
x = ±20
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
20² = 400
400 = 400
(-20)² = 400
400 = 400
Answer:
24%
Step-by-step explanation:
48/248*100
=24%
original 248
new. 200
difference 48
Let a₁ = the first term.
Because each previous term is 1/5 of the value of the current term, the geometric sequence is
a₁, 5a₁, 25a₁, ...,
The common ratio is r = 5.
The n-th term is

The fifth term is 781.25. Therefore
a₁*5⁴ = 781.25
625a₁ = 781.25
a₁ = 1.25
Answer:
The recursive formula is