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lions [1.4K]
3 years ago
9

Work out the lengths of sides a and b.

Mathematics
1 answer:
dexar [7]3 years ago
3 0

Answer:

a = 9.4

b = 12.0

Step-by-step explanation:

Given

See attachment

Required

Determine the values of a and b

To solve for a, we consider the first triangle.

Using Pythagoras:

a^2 = 8^2 + 5^2

a^2 = 64 + 25

a^2 = 89

Take square root of both sides

a = \sqrt{89

a = 9.4 -- approximated

To solve for b, we consider the second triangle.

Using Pythagoras:

17^2 = 12^2 + b^2

289 = 144 + b^2

Collect Like Terms

b^2 = 289 - 144

b^2 = 145

Take square root of both sides

b = \sqrt{145

b = 12.0 --- approximated

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A light bulb consumes 960 watt-hours per day. How many watt-hours does it consume in 3 days and 18 hours?
oksano4ka [1.4K]

960 x 3 = 2880

18/24 = 0.75

960x 0.75 = 720

2880 + 720 = 3600

7 0
3 years ago
Read 2 more answers
A model length of 12 cm. represents an actual length of 102 ft.the model has a width of 48cm. What is the width of the actual ob
Elodia [21]

the answer would be 408


just set it up like this

12       48

----  =  ----

102      ?


12*4=48 so 102*4 = 408

8 0
4 years ago
Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un
stira [4]

Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = 2w+15

width = 2w+9

Area of road with pool =  (2w+15) (2w+9)

= 4w^2+30w+18w+135\\\\=4w^2+48w+135

Area of road = (Area of road with pool ) -(area of pool)

\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\  w=-14\ or \ w=2

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

8 0
4 years ago
14. Find the distance between (7,217pi/180 ) and (5,-23pi/36 ) on the polar plane.
irina [24]

Answer: the distance is  3.49 units

Step-by-step explanation:

There are some ways to find the exact distance, i will calculate the distance in rectangular coordinates.

When we have a point (R, θ) in polar coordinates, we can transform it into rectangular coordinates as:

x = R*cos(θ)

y = R*sin(θ)

Then we have:

(7,217pi/180 )

R = 7

θ = (217/180)*pi

x = 7*cos( (217/180)*pi) = -5.59

y = 7*sin( (217/180)*pi) = -4.21

So this point is (-5.59, -4.21) in rectangular coordinates.

And the other point is  (5,-23pi/36 )

R = 5

θ = -(23/36)*pi

x = 5*cos(  -(23/36)*pi ) = -2.11

y = 5*sin(  -(23/36)*pi ) = -4.53

So this point is (-2.11, - 4.53)

Then the point distance between those points is:

D = I (-2.11, -4.53) - (-5.59, -4.21) I

D = I (-2.11 + 5.59, -4.53 + 4.21) I

D = I (3.48, -0.32) I = √( (3.48)^2 + (-0.32)^2) =  3.49

4 0
3 years ago
-7 opposite and absolute value
77julia77 [94]
It is 7 opposite is different and absolute  value would be 7 also it is always positive
7 0
4 years ago
Read 2 more answers
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