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3 years ago

What is the difference between the first image and the second??

Mathematics

1 answer:

Olenka [21]3 years ago

7 0

Answer:

There is only one image

Step-by-step explanation:

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The system of linear equations -2y+ y = 8 and -3x -y=7 is graphed below. What is the solution to the system of equations?

victus00 [196]

Answer:

x= 1/3

y = -8

Step-by-step explanation:

-2y+ y = 8 equation 1

-3x -y =7 equation 2

using equation 1 we have:

-2y+ y = 8

-y = 8

y = -8 equation 3

using equation 3 in equation 2 we have:

-3x -y=7

-3x -(-8)=7

-3x +8 =7

-3x = 7-8

-3x = -1

x= 1/3

5 0

4 years ago

Read 2 more answers

Please explain who would i be able to get the answer to this problem.

SashulF [63]

We have been an quadratic equation $8k-k^{2} =42$ and we are asked to solve our equation.

Upon subtracting 42 from both sides of our equation we will get,

$8k-k^{2}-42 =0$

$-k^{2}+8k-42 =0$

$k^{2}-8k+42 =0$

Let us check whether our quadratic equation has any real roots using discriminant formula.

$D=b^{2}-4ac$

Upon substituting our given values in discriminant formula we will get,

$D=(-8)^{2} -4(1\cdot 42)$

$D=64 -168$

$D=-104$

We can see that D is less than zero, so our quadratic equation has no real roots.

Now we will use imaginary number i to find complex roots of our quadratic equation.

We will use $-1 =i^{2}$ to solve our equation.

$k=\frac{-b \pm \sqrt{b^{2}-4ac} } {2a}$

$k=\frac{--8 \pm \sqrt{(-8)^{2}-4(1*42)} } {2*1}$

$k=\frac{8 \pm \sqrt{64-168 }} {2}$

$k=\frac{8 \pm \sqrt{-1\cdot 104} } {2}$

$k=\frac{8 \pm \sqrt{i^{2}\cdot 104} } {2}$

$k=\frac{8\pm 2i \sqrt{26}}{2}$

$k=4\pm i \sqrt{26}$

Therefore, our answer will be $k=4\pm i \sqrt{26}$ .

3 0

3 years ago

April, Betty, Carmen and Donna are running in a race. April is winning. Carmen is 12 meters behind April. Betty is 2 meters ahea

Darya [45]

4 meters because Betty is 10 meters behind April. Donna (14 meters behind April) - Betty (10 meters behind April) = Betty (4 meters ahead of Donna).

4 0

3 years ago

Read 2 more answers

ABC Designs, which produces rings, is developing direct material standards. Each ring requires 0.52 kilograms of a special met

Maru [420]

The standard quantity of metal per ring is 0.57 kilograms.

Step-by-step explanation:

Each ring requires 0.52 kilograms of a special metal.

The allowance for waste is 0.03 kilograms per ring, while the allowance for rejects is 0.02 kilograms per ring.

So, the standard quantity of metal per ring = 0.52 kg of metal required + 0.03 kg of allowance for waste + 0.02 kg of allowance for rejects)

= $0.52+0.03+0.02=0.57$ kilograms.

Hence, the standard quantity of metal per ring is 0.57 kilograms.

7 0

4 years ago

How do you find the surface area of a triangular prism

Crazy boy [7]

Type surface area of a triangular prism on google for a calculator

or height X Base side A X base side B X base side C

the base is the triangular side the height is the long part

7 0

4 years ago