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Anestetic [448]
2 years ago
10

Where should you put your money if you want to invest it and make more money from it?

Mathematics
1 answer:
jekas [21]2 years ago
7 0

Whats the answers.............

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How do you determine a function if a relation is a function <br>​
ira [324]

Answer:

Hello! A function is easily identified when an x value does not have more than 1 y value. a y value can have as many x values to infinity, but x can only have one y.

Example...

x                       y

3                       5

4                       5

1                        2

7 0
2 years ago
Plz help Ill give brainliest for first answer
faltersainse [42]

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3 years ago
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Find the 58th term of the following arithmetic sequence.<br> 13, 19, 25, 31,
pashok25 [27]

Answer:

the answer to this is 355.

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6 0
2 years ago
Write a polynomial function of least degree with the given zero. -1+ √ 2, √ 3
kirill115 [55]

Answer:

f(x) = x^{4} + 2x³ - 4x² - 6x + 3

Step-by-step explanation:

Note that radical zeros occur in conjugate pairs, thus

- 1 + \sqrt{2} is a zero then - 1 - \sqrt{2} is also a zero

\sqrt{3} is a zero then - \sqrt{3} is also a zero

Thus the corresponding factors are

(x - (- 1 + \sqrt{2}) ), (x - (- 1 - \sqrt{2}) ), (x - \sqrt{3}), (x - (- \sqrt{3})), that is

(x + 1 - \sqrt{2}), (x + 1 + \sqrt{2}), (x - \sqrt{3}), (x + \sqrt{3})

The polynomial is then the product of the roots

f(x) = (x + 1 - \sqrt{2})(x + 1 + \sqrt{2})(x - \sqrt{3})(x + \sqrt{3})

     = ((x + 1)² - (\sqrt{2})²)((x² - (\sqrt{3})²)

     = (x² + 2x + 1 - 2)(x² - 3)

     = (x² + 2x - 1)(x² - 3) ← distribute

     = x^{4} - 3x² + 2x³ - 6x - x² + 3

     = x^{4} + 2x³ - 4x² - 6x + 3

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3 years ago
Find tan please.make sure to simplify if needed
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What do u want me to solve there is no photo
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2 years ago
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