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3 years ago

What does mean absolute deviation (MAD) measure? Explain how to find the MAD for a set of data.

Mathematics

2 answers:

Elenna [48]3 years ago

8 0

Answer:

Step-by-step explanation:

The MAD is a measure of variability. Find the mean of the data set. Find the distance from the mean for each data value. Find a means of the distances.

BigorU [14]3 years ago

4 0

Mean Absolute Deviation is a quantity of measurement that gives you an idea how far, on average, are the data points deviating from the mean. Its equation is

MAD = ∑|x - μ| / N, where

x is a single data point
μ is the mean of the data set
N is the total number of data points

Suppose, a data set consist of the following: 4, 7, 5, 9, 6, 7, 7, 4. Let's solve first for the mean:

μ = (4+7+5+9+6+7+7+4)/8 = 6.125

Then, the MAD is equal to:

MAD = (|4 - 6.125| + |7 - 6.125| +|5 - 6.125| +|9 - 6.125| +|6 - 6.125| +|7 - 6.125| +|7 - 6.125| +|4 - 6.125|) ÷ 8
MAD = 11/8
MAD = 1.375

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3 years ago

Use trigonometric substitution to evaluate the integral 13 + 12x − x2 dx . First, write the expression under the radical in an a

SCORPION-xisa [38]

I don't see a square root sign anywhere, so I'll assume the integral is

$\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx$

First complete the square:

$13+12x-x^2=49-(6-x)^2=7^2-(6-x)^2$

Now in the integral, substitute

$6-x=7\sin t\implies\mathrm dx=-7\cos t\,\mathrm dt$

so that

$t=\sin^{-1}\left(\dfrac{6-x}7\right)$

Under this change of variables, we have

$7^2-(6-x)^2=7^2-7^2\sin^2t=7^2(1-\sin^2t)=7^2\cos^2t$

so that

$\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx=-7\int\sqrt{7^2\cos^2t}\,\cos t\,\mathrm dt=-49\int|\cos t|\cos t\,\mathrm dt$

Under the right conditions, namely that cos(t) > 0, we can further reduce the integrand to

$|\cos t|\cos t=\cos^2t=\dfrac{1+\cos(2t)}2$

$\displaystyle-49\int|\cos t|\cos t\,\mathrm dt=-\frac{49}2\int(1+\cos(2t))\,\mathrm dt=-\frac{49}2\left(t+\frac12\sin(2t)\right)+C$

Expand the sine term as

$\dfrac12\sin(2t)}=\sin t\cos t$

Then

$t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \sin t=\dfrac{6-x}7$

$t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \cos t=\sqrt{7^2-(6-x)^2}=\sqrt{13+12x-x^2}$

So the integral is

$\displaystyle-\frac{49}2\left(\sin^{-1}\left(\dfrac{6-x}7\right)+\dfrac{6-x}7\sqrt{13+12x-x^2}\right)+C$

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3 years ago

Izumi is running on a quarter-mile oval track. After running 110 yards, his coach records his time as 16 seconds.

pickupchik [31]

Answer:

14.04 miles per hour

Step-by-step explanation:

The problem is asking for Izumi's speed. The formula of speed is:

s = $\frac{d}{t}$ , where "s" means speed, "d" means distance and "t" means time.

The problem is also asking for the unit miles per hour ( $\frac{miles}{hour}$ ) so, this means that we have to know how many miles Izumi ran, given that the problem only mentioned yards (110 yards).