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Savatey [412]
3 years ago
7

WILL MARK BRAINLIEST

Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0

Answer:

the answer is D

Step-by-step explanation:

because it's D

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Ten less than 3 times a numbers is the same as the number plus 4 please help
Dmitry_Shevchenko [17]

7 is the correct answer! :-)

6 0
2 years ago
How do you solve this equation -6x + 7y =13 and -6x +8y =20 using elimination
ohaa [14]

Answer:

x=6,y= 7

Step-by-step explanation:

-6x +7y= 13

-6x+8y=20

-y = -7

divide through by -1

y =7

sub y= 7 in equation 1

then x= 6

8 0
3 years ago
Joe is 1.6m tall. His shadow is 2m long when he stands 3m from the base of a floodlight.height1.6 m2m3mWhat is the height of the
alexdok [17]
We are given the height of Joe which is 1.6 meters, the length of his shadow is 2 meters when he stands 3 meters from the base of the floodlight. 

First, we have to illustrate the problem. Then we can observe two right triangles formed, one is using Joe and the length of the shadow, the other is the floodlight and the sum of the distance from the base plus the length of the shadow. To determine the height of the floodlight, use ratio and proportion:

1.6 / 2 = x / (2 +3)

where x is the height of the flood light

solve for x, x = 4. Therefore, the height of the floodlight is 4 meters.
6 0
3 years ago
Help please <br><br> look at picture <br><br> supplementary angles
8_murik_8 [283]

Answer:

x=16

Step-by-step explanation:

....,...................

5 0
2 years ago
5) Find the equation of the line going through the point (4,1) and<br> perpendicular to y = - 3x +7
vovangra [49]

Answer:

3y=x-1 OR y=⅓x-⅓

Step-by-step explanation:

Lets call the equation y=-3x+7 line l1

the other line passing through (4,1) l2

If two lines are perpendicular,then the product of their roots=-1

That is m(l1)×m(l2)=-1

Slope of l1=-3 therefore slope of l2=-1÷-3=⅓

Now that we have determined the slope of l2 we move on to find it's equation using the point-slope form

y-y1=m(x-x1)

y-1=⅓(x-4)

3y-3=x-4

3y=x-4+3

3y=x-1 OR y=⅓x-⅓

6 0
3 years ago
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