25% is equal to 100/25=1/4

We can substitute this into an equation to get the total number of wells where n can be equal to the total number of wells.

1/4*n=50
n/4=50
n=50*4
n=200

The total number of wells that were drilled was 200.

6 0

2 years ago

Read 2 more answers

A family of 6 is going to the fair. They have a coupon for $1.50 off each ticket. If they pay $46.50 for all their tickets, how

madreJ [45]

Answer:

35.00

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Please help me on this I’m so tired and I can’t sleep until my progress is at 80 and this is the end of my year it’s at 79%

Mice21 [21]

Answer: The bottom one is the answer

Step-by-step explanation:

The one on the right wouldn't be correct because histograms are supposed to always be connected from the beginning of it.

The one on the left is ignoring the fact that 40-59 and 60-79 are two different periods of minutes.

So the only correct on would be the bottom one.

5 0

3 years ago

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

1 year ago