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olga_2 [115]
2 years ago
13

What is the slope of the function represented by the table of values below

Mathematics
1 answer:
Over [174]2 years ago
7 0

Answer:

The correct option is A....

Step-by-step explanation:

We have a table of x,y pairs. To compute the slope we can use any two pairs, say the first two, and plug them into our formula:

m = y2-y1 / x2-x1

m = 5-13/ 0-(-2)

m = -8/0+2

m = -8/2

m = -4

We can check this answer by using a different pair: Take the last two pairs.

m = -27-(-15)/ 8-5

m = -27+15/3

m = -12/3

m = -4

Thus the slope is -4

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Let (8,−3) be a point on the terminal side of θ. Find the exact values of cosθ, cscθ, and tanθ.
denis23 [38]

Answer:

\text{Cos}\theta=\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}

\text{Csc}\theta=-\frac{\sqrt{73}}{3}

\text{tan}\theta =\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}

Step-by-step explanation:

From the picture attached,

(8, -3) is a point on the terminal side of angle θ.

Therefore, distance 'R' from the origin will be,

R = \sqrt{x^{2}+y^{2}}

R = \sqrt{8^{2}+(-3)^2}

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Therefore, Cosθ = \frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}

Sinθ = \frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{y}{R}=\frac{-3}{\sqrt{73} }

tanθ = \frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}

Cscθ = \frac{1}{\text{Sin}\theta}=\frac{R}{y}=-\frac{\sqrt{73}}{3}

6 0
4 years ago
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