Answer: 1) AC = 13
The formua does not actually apply to all of the problems.
Step-by-step explanation:
1) The absolute value of -8 is added to the absolute value of 5. 8+5=13
2) Subtract the length of the EF from EG to get the length of FG 21 -6 = 15
3) Take what's given and create an equation to solve. 4x + 15 +39 =110. 4x = 110 - (15+39).
4x =110-54. 4x =56. x=56/4. x=14
4) Create another equation. You have two segments that add up to the length of EG, given =23
EF+FG=EG
(2x-12)+(3x-15)=23
5x - 27 = 23
5x= 23+27 5x =50. x = 10
Substitute 10 for x
EF=2(10) -12 EF=8
FG=3(10)-15. FG=15
EF+FG =EG.
8 + 15 = 23
5) 2/5 of 25 is 10 So EF is 10. Subtract from 25 to get FG
FG = 15
I hope this helps you.
We develop an equation for the given situation by first writing the general equation for lines,
y = mx + b
Substituting to this given the values given above,
(1990) 430 = b
(2000) 400 = m(10) + 430
The value of m from the equation in 2000 is -3. Thus, the equation of that relates the variables is,
y = -3x + 430
It is D, because 5.098 times 10 to the power of 6 does equal 5098000
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- t
The equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)
Let l be the original length of the pool.
Since the length of the pool is increased by 3.7 m, the new length L = l + 3.7.
Also, the area of the pool A = 205.85 square meter and it is a rectangle with width, W = 11.6 meters,
So, A = LW
Substituting the values of the variables into the equation, we have
A = LW
205.85 = (l + 3.7)11.6
So, the equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)
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