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MissTica
3 years ago
5

Suppose X is normally distributed with mean 20 and standard deviation 4, find the value x0 such that P(X ≥ x0) = 0.975.

Mathematics
1 answer:
abruzzese [7]3 years ago
7 0

Answer:

12.16

Step-by-step explanation:

From your question, we have the following information

Mean = u = 20

Standard deviation sd = 4

P(X>Xo) = 0.975

1-0.975 = 0.025

P(z<Xo-20/4) = 0.025

Xo-20/4 = -1.96

We cross multiply

Xo - 20 = -1.96 x 4

Xo - 20 = -7.84

Xo = -7.84+30

Xo = 12.16

12.16 is the value of Xo and therefore the answer to this question.

Thank you!

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dalvyx [7]

Answer:

2x-9y=-51

2x-3y=-9

subtract question ii from i we get

-6y = -42

y =7

put value of y in 1

2x - 63 = -51

2x= 8

x=4

3 0
3 years ago
If C(x) = 4x^2 - 3, find the following<br> (a) C(0)<br> (b) C (-1)<br> (c) C (-2)<br> (d) C (-3/2)
NeTakaya

Step-by-step explanation:

C(x)=4x^2-3\\\\C(0),\ C(-1),\ C(-2),\ C\left(-\dfrac{3}{2}\right)\\\\\text{Substitute each value}\ \left\{0, -1, -2, -\frac{3}{2}\right\}\ \text{instead}\ C(x):\\\\C(0)=4(0^2)-3=4(0)-3=0-3=-3\\\\C(-1)=4(-1)^2-3=4(1)-3=4-3=1\\\\C(-2)=4(-2)^2-3=4(4)-3=16-3=13\\\\C\left(-\dfrac{3}{2}\right)=4\left(-\dfrac{3}{2}\right)^2-3=4\left(\dfrac{9}{4}\right)-3=9-3=6

3 0
3 years ago
HELP
3241004551 [841]
This might be the answer but I no sure

8 0
3 years ago
Solve the problem. six times Tim’s age is 54. His sisters age times three is also 54. How old are Tim an his sister Amy?
Semenov [28]

If t is Tim's age, then 6t=54, so t=9.

If a is Amy's age, then 6a=54, so her age is also a=9.

6 0
3 years ago
suppose that the lifetime of a transistor is a gamma random variable x with mean of 24 weeks and standard deviation of 12 weeks.
emmainna [20.7K]

The probability that the transistor will last between 12 and 24 weeks is 0.424

X= lifetime of the transistor in weeks E(X)= 24 weeks

O,= 12 weeks

The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.

X~gamma(\alpha ,\beta)

E(X)= \alpha \beta                 \beta= 12^{2}/24=6 weeks

V(x)= \alpha \beta ^{2}                \alpha=24/6= 4

Now we can find the solutions:

The excel formula used to create Figure one is as follows:

=gammadist(X, \alpha, \beta, False)

P(12\leq X\leq 24)

P(12/6\leq G\leq 24/6)

P(2\leq G\leq 4)

P= 0.424

Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424

To learn more about probability click here:

brainly.com/question/11234923

#SPJ4

4 0
1 year ago
Read 2 more answers
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