Suppose X is normally distributed with mean 20 and standard deviation 4, find the value x0 such that P(X ≥ x0) = 0.975.
1 answer:
Answer:
12.16
Step-by-step explanation:
From your question, we have the following information
Mean = u = 20
Standard deviation sd = 4
P(X>Xo) = 0.975
1-0.975 = 0.025
P(z<Xo-20/4) = 0.025
Xo-20/4 = -1.96
We cross multiply
Xo - 20 = -1.96 x 4
Xo - 20 = -7.84
Xo = -7.84+30
Xo = 12.16
12.16 is the value of Xo and therefore the answer to this question.
Thank you!
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Answer:
The coordinates of P' are (4.8,-4.8).
Step-by-step explanation:
The rule of dilation represent the dilation with scale factor 2.4 and center at origin.
If the scale factor of the dilation is k and the center is (0,0), then
Since the scale factor is 2.4, therefore
From the given figure it is noticed that the coordinates of P are (2,-2). The coordinates of P' are
Therefore the coordinates of P' are (4.8,-4.8).
Slope of a line passing through these two points is .
Hope this helps.