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hjlf
3 years ago
10

What are the coordinates of the vertex of the function y-11=-(x-5)^2?

Mathematics
1 answer:
Darina [25.2K]3 years ago
8 0
The answer to the question is y=<span><span><span>−<span>x2</span></span>+<span>10x</span></span>−<span>14</span></span>
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Find the product and 220 and 4
Alecsey [184]
220 x 4 = 880. //////
6 0
3 years ago
Read 2 more answers
If x = 1 is a common root of ax² +ax + 2 = 0 and x² + x + b = 0 , then ab =
vodka [1.7K]

Answer:

ab = 2

Step-by-step explanation:

Given equations

ax² +ax + 2 = 0

x² + x + b = 0

root of both the equation

x= 1

then we can plug in x = 1 in both the equation

ax² +ax + 2 = 0                        x² + x + b = 0

a*1² +a*1 + 2 = 0                        1² + 1 + b = 0

a +a + 2 = 0                                 1 + 1 + b = 0

2a + 2 = 0                                    2 + b = 0

2a = -  2                                         b = -2

a = -2/2 = -1

Thus,

a = -1

b = -2

a*b = -1*-2 = 2

ab = 2

6 0
3 years ago
At the store for every 6 books sold there were 5 movies sold. What is the ratio of books sold to movies sold?
tatyana61 [14]

Answer:

6,5

Step-by-step explanation:

6 + 5 = 11

6 to 5

6,5

3 0
3 years ago
Determine which equation is parallel to the line JK and which is perpendicular to like JK
sattari [20]

Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and y = - \frac{1}{m}x + b will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as  

y = mx + c ............. (1)

Therefore, the equation has slope = m

Now, any straight line having an equation with slope m will be parallel to line JK.

So, the equation of the straight line which is parallel to equation (1) will be  

y = mx + c', where, c' is any real constant.

Now, let us assume that another straight line having equation  

y = nx + a is perpendicular to the line JK i.e. equation (1).

Now, we know if two lines are perpendicular to each other then the product of their slopes will be - 1.

So, mn = - 1

⇒ n = - \frac{1}{m}

Therefore, the equation of a straight line which is perpendicular to equation (1) will be y = - \frac{1}{m}x + b where b is any real constant. (Answer)

3 0
3 years ago
Read 2 more answers
What is 271,403 rounded to the nearest thousand?
Jobisdone [24]

271,403 = 271,400 is the answer

5 0
3 years ago
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