What are the coordinates of the vertex of the function y-11=-(x-5)^2?
1 answer:
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Answer:
a. Vertex = (2.5,-12.25)
b. y-intercept = (0,-6)
c. x-intercept = (6,0) ; (-1,0)
Step-by-step explanation:
a.
Your equation is written as:
The easiest way to find the vertex is writing the equation this way:
Being the vertex (h,k)
So first complete the square
Vertex : (2.5,-12.25)
b.
To find the y-intercept you need to replace the equation when x = 0 and get y
c.
To find the x-intercept you need to replace the equation when y = 0 and get x