What are the coordinates of the vertex of the function y-11=-(x-5)^2?

1 answer:

8 0

The answer to the question is y=−x2+10x−14

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zzz [600]

The answer is not in the choices so ... but the (0,4), (1,1), (2,6)

Hope This Help.

Xd <3

6 0

2 years ago

Alexandra [31]

Answer:

tHANKS FOR THE POINT

Step-by-step explanation:

6 0

3 years ago

defon

Answer:

r=1

Step-by-step explanation:

-4 r -10r + -5= -19

-4r + (-10r) + -5=-19

-14r+ -5 = -19

-14r + -5 +5= -19+5

-14r= -14

r=1

5 0

3 years ago

alexdok [17]

Answer:

t = 12

Step-by-step explanation:

252 divded by 21 =

 $12$ '

8 0

3 years ago

Verdich [7]

That would be -0.041

-0.125/3 = -0.041666666

5 0

2 years ago