Hi i need to identify the congruence postulation i think i need help.

A friend of yours was interested in determining whether the news media noticed campus events. Your friend decided to do a conten

anygoal [31]

The inference is that the person will tell the friend that he did manifest coding and he should have recorded the base.

<h3>What is an inference?</h3>

The options are:

He did manifest coding.

He did latent coding.

He should have recorded the base.

He did manifest coding and he should have recorded the base.

It should be noted that an inference simply means the conclusion that can be deduced based on the information given.

In this case, the friend was interested in determining whether the news media noticed campus events and decided to do a content analysis of the local paper.

Therefore, the the person will tell the friend that he did manifest coding and he should have recorded the base.

Learn more about inference on:

brainly.com/question/25280941

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8 0

2 years ago

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Pls help it’s not 2 and not 10

eduard

Answer:

11.18

Step-by-step explanation:

6 0

3 years ago

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5. Suppose that a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organ

mart [117]

Answer:

Probability that the sample proportion will be greater than 0.5 is 0.8133.

Step-by-step explanation:

We are given that the a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organization is about to take a simple random sample of voters and will use the sample proportion to estimate p.

Suppose that the polling organization takes a simple random sample of 500 voters.

<em>Let </em> $\hat p$ <em> = sample proportion</em>

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion = 48%

n = sample of voters = 500

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be greater than 0.5 is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.50) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\frac{0.50-0.48}{\sqrt{\frac{0.50(1-0.50)}{500} } }$ ) = P(Z < 0.89) = 0.8133

<em>Now, in the z table the P(Z </em> $\leq$ <em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.89 in the z table which has an area of 0.8133.</em>