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3 years ago

Hi i need to identify the congruence postulation i think i need help.

Mathematics

1 answer:

ozzi3 years ago

3 0

What do you need help with exactly

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Mohit pays rupees 9000 as an amount on the sum of rupees 7000 that he had borrowed for 2 years.

Sphinxa [80]

Answer:

The required rate of interest = 14.285%

Step-by-step explanation:

Here, The principal amount = 7,000

The final paid amount = 9,000

Time = 2 years

Let us assume the rate of interest = R

Now, Simple Interest = Amount - Principal

= 9,000 - 7,000 = 2,000

So, the SI on the given principal for 2 years = 2,000

$\textrm{SIMPLE INTEREST } = \frac{P \times R \times T}{100}\\\implies 2000 = \frac{7,000 \times R \times 2}{100}\\\implies R = \frac{2,000 \times 100}{7,000 \times 2} = 14.285$

or, R = 14.285%

Hence, the required rate of interest = 14.285%

8 0

3 years ago

9 x 10 to the power of 2 how many times as much as 3 x 10 to the -2 power

hjlf

Answer:

3×10^4

Step-by-step explanation:

The desired factor is found by calculating the ratio of the two numbers:

k = (9×10^2)/(3×10^-2) = (9/3)×10^(2 -(-2)) = 3×10^4

The first number is 3×10^4 = 30,000 times as much as the second number.

6 0

2 years ago

You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

7 0

2 years ago

Select all that apply.

ioda

Answer:

multiply 6:8 by 2

12:16

6 0

2 years ago

Enguun earns $17 per hour tutoring student athletes at Brooklyn University. a) If Enguun tutored for 12 hours this month, how mu

Sati [7]

Answer: a) $204 b) $331.50

Step-by-step explanation: a) 17 x 12 b) 17 x 19.5 (Sorry, I can't do a diagram, you have to do it by yourself...)

6 0

2 years ago

Hi i need to identify the congruence postulation i think i need help.​

Hi i need to identify the congruence postulation i think i need help.