Question in English:
A female carries a recessive lethal gene (l) on one of her X chromosomes, and a normal dominant allele (L) on the other. What is the sex ratio to be expected in this woman's dependency if she marries a normal man?
Answer:
2/3 females
1/3 males
Explanation:
Females have two X chromosomes (XX) and males have an X and a Y chromosome (XY).
The genotype of the female is XLXl. The genotype of the male is XLY, since he is normal.
The possible genotypes are:
<u> XL Xl</u>
<u>XL</u> <em>XLXL XLXl</em>
<u>Y</u> <em>XLY </em><em>XlY</em>
<em />
All female offspring will be normal as they will always have one normal copy of the X chromosome from their father.
50% of the male offspring will be normal, but 50% will inherit the lethal gene from their mother.
Because the allele is lethal, that means XlY males will not be born.
That means 2/3 of the children will be females, and 1/3 will be males.
Answer:
The Answer is, B, C, And E. I just took it on USATESTPREP.
B) G3P can be used to form the backbone of triglycerides. Glycerol combines with fatty acid tails to form lipids.
C) Two G3P molecules can be combined through anabolic processes to form glucose, a six-carbon sugar required by cells.
E) G3P can be used in to synthesize amino acids, which contain a central carbon, a carboxylic acid group, and a variable R group. These amino acids can then combine to form proteins.
No! matter is not created nor distroyed
YOU HAVE TWO LOOK AT BOTH
