All categories

2 years ago

8 * 6 + (12-4) / 2 equals to what

Mathematics

1 answer:

Cloud [144]2 years ago

4 0

Answer:

Step-by-step explanation:

Simplify the expression (Steps shown below).

You might be interested in

At 10:00 AM Han and Tyler

NARA [144]

Eat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butteat butt

6 0

2 years ago

Find the equation of the following graph:

topjm [15]

Answer:

3cos(3t)

ebevube7jeu2hwhuebeyeb

3 0

2 years ago

Given the graph below, which of the following statements is true?

nirvana33 [79]

Answer:

D) The graph does not represent a one-to-one function because the y-values between 0 to 2 are paired with multiple x-values.

Step-by-step explanation:

Let's find the ordered pairs.

(-4, 4), (-3, 2), (-2, 0), (-1, 0.5), (0, 1), (1, 1.5), (2, 2), (3, 0)

The graph passed through above points.

In the x-coordinates -3, 2 gives the same output. Therefore, the given function is not one-to-one.

Therefore, the answer D)

The graph does not represent a one-to-one function because the y-values between 0 to 2 are paired with multiple x-values.

Hope you will understand the concept.

Thank you.

7 0

2 years ago

3. What is the distance between -49 and 167?

Salsk061 [2.6K]

Answer:

c) IS THE ANSWER

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Find (a) arc length and (b) Area of a sector.

barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

<u>Calculation</u>

Given:

$\theta=\dfrac{5 \pi}{8}$
r = 15 cm

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}$

5 0

1 year ago