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frez [133]
3 years ago
11

Help please! Any help is very much appreciated :)

Mathematics
1 answer:
lesya [120]3 years ago
6 0

I am not good at this but I think it is 13

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If cosine theta equals negative square root of three over two and pi over two less than theta less than pi, what are the values
Natalka [10]
<h2>Answer:</h2>

The values of sinθ and tanθ are:

\sin \theta=\dfrac{1}{2}

and

\tan \theta=-\dfrac{1}{\sqrt{3}}=-\dfrac{\sqrt{3}}{3}

<h2>Step-by-step explanation:</h2>

It is given that:

\cos \theta=-\dfrac{\sqrt{3}}{2}

where

\dfrac{\pi}{2}

i.e. the angle θ lie in the second quadrant.

Also, we know that in the second quadrant sine and cosecant function is positive.

whereas cosine,secant, tangent and cotangent functions are negative.

Now, we know that:

\cos (\dfrac{5\pi}{6})=-\dfrac{\sqrt{3}}{2}

i.e. here

\theta=\dfrac{5\pi}{6}

Hence, we have:

\sin (\theta)=\sin (\dfrac{5\pi}{6})\\\\i.e.\\\\\sin \theta=\dfrac{1}{2}

Also,

\tan \theta=\dfrac{\sin \theta}{\cos \theta}\\\\i.e.\\\\\tan \theta=\dfrac{\dfrac{1}{2}}{\dfrac{-\sqrt{3}}{2}}\\\\i.e.\\\\\tan \theta=\dfrac{1}{-\sqrt{3}}\\\\i.e.\\\\\tan \theta=-\dfrac{1}{\sqrt{3}}

Now, on rationalizing we have:

\tan \theta=-\dfrac{\sqrt{3}}{3}

7 0
4 years ago
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I NEED HELP Please ☺️☺️☺️☺️☺️
UkoKoshka [18]
C = 2×pi×r
72 = 2×pi×r

so r = 36/pi

DE = 30deg×36/pi
DE = (pi/6)×(36/pi) = 6cm
7 0
3 years ago
9.
Contact [7]

a = 640s

a = 640(7.5)

a = 4800 \:

She owns 4800 acres.

5 0
3 years ago
Read 2 more answers
................,,,,,,,,,,,,,,,,,,,,,,,,,,,,
puteri [66]

Answer:

96

bcs the exercise room is 70

weight room is 42

but they both include locker room

the locker room is 16

locker room calculated twice

so 70 + 42 - 16 = 96

7 0
2 years ago
What is 4.89 times 6.3
velikii [3]

Answer:

30.807

Step-by-step explanation:

Hope this helps

4 0
4 years ago
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