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Crazy boy [7]
3 years ago
15

I need help plss. I will give you a lot of points I promise

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
8 0
Slope=0.005/2.000=0.002
p - intercept = 974/1 = 974.00000
n- intercept = 974/-404 = 487/-202 = -2.41089


Oh and it is ok if you don’t have a lot of points I am great full for the points you are giving me and the answer is C)13,094 and can I have the brainliest since the other guy clearly did not answer the question right I only have one brainliest ☺️
krok68 [10]3 years ago
8 0
I think the answer is C
Hope it right
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marishachu [46]
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Help Please. I'm no good when it comes to math
Natali [406]

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7 0
3 years ago
∫(cosx) / (sin²x) dx
kirza4 [7]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822772

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\&#10;=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}


Make the following substitution:

\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}


and then, the integral (i) becomes

=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\&#10;=\mathsf{\displaystyle\int\! u^{-2}\,du}


Integrate it by applying the power rule:

\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\&#10;\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\&#10;\mathsf{=-\,\dfrac{1}{u}+C}


Now, substitute back for u = sin x, so the result is given in terms of x:

\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\&#10;\mathsf{=-\,csc\,x+C}


\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

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3 years ago
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