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3 years ago

Find the inequality represented by the graph. Thanks! (plz no spam...)

Mathematics

2 answers:

nikitadnepr [17]3 years ago

6 0

Answer:

y > (1/3)x - 3.

Step-by-step explanation:

The graph of a line can be written in y = mx + b form where b is the y-intercept and m is the slope.

In the image, the slope of the graph from the given points is 1/3.

In the image, the y-intercept is -3.

Therefore, the line is y = (1/3)x -3. However, we aren’t done yet! This is an inequality, not an equation!

We see the line isn’t dotted, so that means it must be > or <.

We substitute the point (0,0) into the line equation we got and find that 0 > (1/3)(0) - 3 = -3. Since (0,0) is part of the inequality, we have that y > (1/3)x - 3.

I hope this helps! :)

Leona [35]3 years ago

4 0

Answer:

y > (1/3)x - 3.

Step-by-step explanation:

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3 years ago

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zvonat [6]

Answer:

Step-by-step explanation:

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3 years ago

What’s the answer to this

Andrews [41]

Answer:

A point on either side of the line

Step-by-step explanation:

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3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

Freddie made the number line below to model the laps he walks around a track at his

Elena-2011 [213]

Answer:

On a standard running 400-meter track a mile is 4 laps… plus 9 more meters if you want to get all technical about it. A mile is specifically 1,609.3 meters.

Step-by-step explanation:

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3 years ago