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Marrrta [24]
3 years ago
8

The Wright Flyer was the first successful powered aircraft. A model was made to display in a museum with the length of 35 cm and

a wingspan of about 66.9 cm. The length of the actual plane was 21 ft 1 in., and the height was 2.74 m. Compare the length, height, and wingspan of the model to the actual plane and explain why any errors may occur. (Round any calculations to the nearest whole number.)
Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

<span>To link the displayed Wright flyer in the museum with the actual plane, we have to calculate for the relation of the corresponding parameter. In this problem, for both the display and the actual plane, we are given with the length. Computing for the ratio gives us,</span>

<span>
    ratio = length of the model / length of the actual plane

Length of the model = 35 cm</span>

<span>
We need to calculate for the length of the model in ft.</span>

<span>
length of the model = (35 cm)(1 in/2.54 cm)(1 ft/12 in)
length of the model = 1.148 ft

</span>

<span>
</span>

<span>Going back to the calculation for the ratio,
ratio = (1.148 ft)/21 ft
ratio = 0.055

Therefore, the measurements used in the model is equal to 0.055 times the actual dimensions.

Error may occur because of the number of significant figures measured for rounding up or down of the answers after each calculation. </span>

IJ
3 years ago
How did you get the answer?
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Helppppppp show the steps to your answer
Studentka2010 [4]

The numeric value of the expression -a² - 2bc - |c| for a = -3, b = -5 and c = 2 is of 9.

<h3>How to find the numeric value of an expression?</h3>

The numeric value of an expression is found replacing each letter by it's attributed value.

In this problem, the expression is:

-a² - 2bc - |c|

The attributed values are:

a = -3, b = -5 and c = 2

Hence the numeric value will be given by:

-a² - 2bc - |c| = -(-3)² - 2(-5)(2) - |2| = -(9) + 20 - 2 = -9 + 18 = 9.

More can be learned about the numeric value of an expression at brainly.com/question/14556096

#SPJ1

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