Vertex form is f(x) = a(x - b)^2 + c where the vertex is (b, c) and a is some constant.
So for the first part we have f(x) = a(x + 6)^2 - 1
for root -9:- a( -9+6)^2 - 1 = 0
9a - 1 = 0 , a = 1/9
The other 3 are derived in the same way.
so required equation is f(x) = (1/9)(x + 6)^2 - 1
Answer:
6/8 y=79
my id has now been sent off
523.6 m3 i hope this helps mark me as brainliest
X/4 = -9
x/4 = -9/1
cross multiply
x = -36
