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Mashutka [201]
3 years ago
8

What is the range of g(x)=3|x-1|-1?

Mathematics
1 answer:
Oduvanchick [21]3 years ago
4 0
The rang is negative infinity to positive infinity is
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-3(4u-v)-5(-v+3u)<br> For 20 points
natita [175]

Answer:

−27u + 8v

Explanation:

−3(4u − v) − 5( − v + 3u)

[ Distribute ]

= (−3)(4u) + (−3)(−v) + (−5)(−v) + (−5)(3u)

= −12u + 3v + 5v + −15u

[ Combine Like Terms ]

= −12u + 3v + 5v + −15u

= (−12u + −15u) + (3v + 5v)

= −27u + 8v

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Brums [2.3K]

Answer:

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Help fast pls!!!!!
AleksandrR [38]

Answer:

Step-by-step explanation:

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Answer:

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