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3 years ago

The list of accounts of Guardian Company contained the following information:

Mathematics

1 answer:

iren [92.7K]3 years ago

5 0

Answer:

sorry I don't know the answer ,but I want to ask u something ,r u a accounting student if yes please comment.i am also a accounting student but on learning stage so I don't know the answer,

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10 POINST!!!<br> What is the area of quadrilateral QRST if QS=18 and RT=24? Show your work.

Allisa [31]

Answer:

area= 1/2 × d1 ×d2

d = diagonal

area= 1/2 ×24×18 =216 unit^2

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3 years ago

Cara wants to buy a television that cost $500 including taxes to pay for the television he would use a payment plan that require

PtichkaEL [24]

Answer:

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brainly.com/question/22157981Step-by-step explanation:

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3 years ago

Read 2 more answers

Hello I need help on this math question

Licemer1 [7]

Answer:

94.2 in squared

Step-by-step explanation:

lateral area plus area of both flat sides

37.68 + 2(3.14*3^2)

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2 years ago

Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow

prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

$CI=\hat{Y}\pm t_{Critical}\times S_{e}$

Where,

$\hat{Y}=$ predicted value of lead content when traffic flow is 15.

$\to df=n-1=8-1=7$

$95\% \ CI\ is\ (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\$

$=\frac{1059.8}{2}\\\\=529.9$

Calculating thet-critical value $t_{ \{\frac{\alpha}{2},\ df \}}=-2.365$

The lower predicted value $=529.9-2.365(Se)$

$463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076$

When $99\%$ of CI use as the expected lead content: $\to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)$

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2 years ago

Help please! It’s due today

docker41 [41]

2 because if you divide 14 by 7 to isolate the variable you get 2

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3 years ago