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3 years ago

Which one is greater? 0.5 or 1/3

Mathematics

2 answers:

fredd [130]3 years ago

7 0

The answer is 0.5 because 0.5 is 1/2 in fraction form.

gavmur [86]3 years ago

6 0

0.5 is greater because 1/3 in decimal form is 0.33333.....

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Julie multiplies 6.27 by 7 and claims the product is 438.9. Explain without multiplying how you know Julie’s answer is not corre

vekshin1

This is because 7 x 6 is only 42 therefore julies answer is way too far off.

the real answer is 43.89

hope this helps you

4 0

3 years ago

What is the area of a rectangle with vertices at (−4, 0) , (−3, 1) , (0, −2) , and (−1, −3) ? Enter your answer in the

Kobotan [32]

What we know:
Area=l x w
vertices at (-4,0),(-3,1), (0,-2),(-1,-3)
pythagorean formula=a²+b²=h²

What we need to find:
Area

Finding length:
Length of rectangle is from point (-4,0) to (-1,-3), found it by plotting the points on graph paper. Went down 3 units and right 3 units to go from one point to the other, these are the a and b in the pythagorean formula.

a²+b²=h²
(3)²=(3)²=h²
9+9=h²
18=h²
√18=√h²
√18=h

Finding width:
Width of rectangle is from point (-4,0) to (-3,1), found it by plotting the points on graph paper. Went up 1 unit and right 1 unit to go from one point to the other, these are the a and b in the pythagorean formula.

a²+b²=h²
(1)²+(1)²=h²
1+1=h²
2=h²
√2=√h²
√2=h

Now we can find area,
Area= l x w
= √18 x√2
=√36=6
Area=6

Remember that when we square root a number we get two solutions, one negative and one positive but since length, width and area are positive we only use positive solutions.

3 0

3 years ago

ILL GIVE BRAINLIEST The graph below have the same shape. What is the equation of the blue graph?

tino4ka555 [31]

Answer:

B) $G(x)=(x+1)^2$

Step-by-step explanation:

3 0

3 years ago

Pleeease open the image and hellllp me

Verdich [7]

1. Rewrite the expression in terms of logarithms:

$y=x^x=e^{\ln x^x}=e^{x\ln x}$

Then differentiate with the chain rule (I'll use prime notation to save space; that is, the derivative of y is denoted y' )

$y'=e^{x\ln x}(x\ln x)'=x^x(x\ln x)'$

$y'=x^x(x'\ln x+x(\ln x)')$

$y'=x^x\left(\ln x+\dfrac xx\right)$

$y'=x^x(\ln x+1)$

2. Chain rule:

$y=\ln(\csc(3x))$

$y'=\dfrac1{\csc(3x)}(\csc(3x))'$

$y'=\sin(3x)\left(-\cot^2(3x)(3x)'\right)$

$y'=-3\sin(3x)\cot^2(3x)$

Since $\cot x=\frac{\cos x}{\sin x}$ , we can cancel one factor of sine:

$y'=-3\dfrac{\cos^2(3x)}{\sin(3x)}=-3\cos(3x)\cot(3x)$

3. Chain rule:

$y=e^{e^{\sin x}}$

$y'=e^{e^{\sin x}}\left(e^{\sin x}\right)'$

$y'=e^{e^{\sin x}}e^{\sin x}(\sin x)'$

$y'=e^{e^{\sin x}+\sin x}\cos x$

4. If you're like me and don't remember the rule for differentiating logarithms of bases not equal to e, you can use the change-of-base formula first:

$\log_2x=\dfrac{\ln x}{\ln2}$