Answer:
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Answer:
Step-by-step explanation:
acceleration, a = 20 m/s^2
initial velocity, u = 0 since it starts from rest
final velocity, v = 400 m/s
v = u + at
400 = 0 + 20 t
400 = 20 t
t = 400 / 20
<u><em>t = 20 sec</em></u>
Hope this helps
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Answer:
t_a = 7 s
t_w = 5 s
Step-by-step explanation:
Given:
- The average speed in air v_a = 16 m/s
- The average speed in water v_w = 3 m/s
- The total distance D = 127 m
- The total time T = 12 s
Find:
How long did the stone fall in air and how long did it fall in the water?
Solution:
- Lets time taken by stone to drop through air as t_a = t_a.
- The time taken in water would be t_w = (12 - t_a)
- The total distance covered can be calculated as:
D = v_a*t_a+ v_w*(12 - t_a)
127 = 16*t_a + 3*(12 - t_a)
Simplify and solve for t:
91 = 16*t_a - 3t_a
13*t_a = 91
t_a = 7 s
t_w = 5 s
