Easy, the second one. Both figures seem congruent.
13 cm+ 13 cm= 26 cm, 26 cm is the answer to Part B.
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
Answer:
4 i think, sorry if incorrect
Step-by-step explanation:
<h3>
Answer: -7</h3>
Explanation:
Pick any term. Subtract off the previous one to find the common difference.
- term2 - term1 = 6-13 = -7
- term3 - term2 = -1-6 = -7
- term4 - term3 = -8-(-1) = -8+1 = -7
And so on. You only need to pick one of those to show as your steps to your teacher. However, doing all three subtractions is a good way to get practice in seeing how we have an arithmetic sequence. The common difference must be the same each time.
We subtract 7 from each term to get the next term, i.e. we add -7 to each term to get the next one.
