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sasho [114]
3 years ago
8

Perimeter/area (triangles) ! PLZ HELP

Mathematics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

12 ft

50\:  ft^2

Step-by-step explanation:

1) since both the triangles are congruent, so their perimeters will also be equal.

Perimeter of triangle CBD = 12 ft

2) since, both the triangles are congruent, so their areas will be equal.

So, Area of rectangle ABCD = 2*25 = 50 square ft

BartSMP [9]3 years ago
3 0

Answer:

50ft^2

Step-by-step explanation:

area of triangle ABC=25ft^2

both triangle have equal area and all together it makes a rectangle ABCD so ,

rect. ABCD=25+25=50FT^2

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6 0
3 years ago
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for the linear function f, the graph of y=f(x) in the xy-plane passes through the points (0,2) and (9,9). what is the slope of y
Bas_tet [7]

Answer:

slope =  \frac{(y _{2} - y _{1})}{(x _{2}  - x _{1})}  \\  = \frac{(9 - 2)}{(9 - 0)}  \\  =  \frac{7}{9}  \\ hence \: slope \: is \:  \frac{7}{9}

5 0
3 years ago
If 4g^2 -1= 16h^2 -1, what is the value of g in terms of h?<br> Plz explain
ale4655 [162]

Answer:

g = ±2h

Step-by-step explanation:

4g^2 -1= 16h^2 -1

Add 1 to each side

4g^2 -1+1= 16h^2 -1+1

4g^2 = 16h^2

Divide each side by 4

4/4g^2 = 16/4h^2

g^2 = 4 h^2

Take the square root of each side

sqrt(g^2) = ±sqrt(4h^2)

g = ±sqrt(4h^2)

g = ±2h

5 0
3 years ago
What is the measure of arc KL?<br><br> 20°<br> 40° <br> 48° <br> 96°
mash [69]

The question is incomplete. The complete question is here

Angle KJL measures (7x - 8)° and angle KML measures (3x + 8)°. What is the measure of arc KL, if M and J lie on the circle ?

Answer:

The measure of arc KL is 40° ⇒ 2nd answer

Step-by-step explanation:

In any circle:

  • Inscribed angles subtended by the same arc are equal
  • If the vertex of an angle lies on the circles and its two sides are chords in the circle, then it called inscribed angle
  • The measure of an inscribed angle is equal to half the measure of its subtended arc

In a Circle

∵ M lies on the circle

∵ KL is an arc in the circle

∴ MK and ML are chords in the circle

∴ ∠KML is an inscribed angle subtended by arc KL

∵ J lies on the circle

∵ KL is an arc in the circle

∴ JK and JL are chords in the circle

∴ ∠KJL is an inscribed angle subtended by arc KL

∵ Inscribed angle subtended by the same arc are equal

∴ m∠KML = m∠KJL

∵ m∠KML = (3x + 8)°

∵ m∠KJL = (7x - 8)°

- Equate them to find x

∴ 7x - 8 = 3x + 8

- Subtract 3x from both sides

∴ 4x - 8 = 8

- Add 8 to both sides

∴ 4x = 16

- Divide both sides by 4

∴ x = 4

- Substitute the value of x in the m∠KML OR KJL to find its measure

∵ m∠KML = 3(4) + 8 = 12 + 8

∴ m∠KML = 20°

∴ m∠KJL = 20°

∵ The measure of an inscribed angle is equal to half the measure

   of its subtended arc

∴ m∠KML = \frac{1}{2} (m of arc KL)

∵ m∠KML = 20°

∴ 20 = \frac{1}{2} (m of arc KL)

- Multiply both sides by 2

∴ 40° = m of arc KL

The measure of arc KL is 40°

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3 years ago
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Is this correct?!?! Pls let me know
goldenfox [79]

Answer:

Nope. It isn't.

Step-by-step explanation:

6^2 + 8^2 = 100, and 100 = 10^2. So that means that the thing that you chose is incorrect.

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