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sasho [114]
3 years ago
8

Perimeter/area (triangles) ! PLZ HELP

Mathematics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

12 ft

50\:  ft^2

Step-by-step explanation:

1) since both the triangles are congruent, so their perimeters will also be equal.

Perimeter of triangle CBD = 12 ft

2) since, both the triangles are congruent, so their areas will be equal.

So, Area of rectangle ABCD = 2*25 = 50 square ft

BartSMP [9]3 years ago
3 0

Answer:

50ft^2

Step-by-step explanation:

area of triangle ABC=25ft^2

both triangle have equal area and all together it makes a rectangle ABCD so ,

rect. ABCD=25+25=50FT^2

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Answer:

  2x² +5x -12 = 0

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2 years ago
Roman stands across from a flag pole.
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we use trigonometry ratios.
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cos 39° = x / 17
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Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
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Answer:

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Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

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So, we have:

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Convert to radians (Multiply both angles by \pi/180)

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\theta = \frac{\pi}{6}, \frac{11\pi}{6}

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