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inysia [295]
3 years ago
8

3(2y + 3) = 1(y + 1)

Mathematics
2 answers:
hammer [34]3 years ago
8 0

Answer:

y = -1 .6

Step-by-step explanation:

777dan777 [17]3 years ago
5 0

Answer:

 =  − 8/5

Step-by-step explanation:

Distribute

3

(

2

+

3

)

=

1

(

+

1

)

6

+

9

=

1

(

+

1

)

Multiply by 1

6

+

9

=

1

(

+

1

)

6

+

9

=

+

1

Subtract  

9

9

9

from both sides of the equation

6

+

9

=

+

1

6

+

9

−

9

=

+

1

−

9

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Vehicles leave an airport parking facility (arrive at parking fee collection booths) at a rate of 500 veh/h (the time between ar
Nutka1998 [239]

Answer:

At least 3 processing booths should be open.

Step-by-step explanation:

1 vehicle spends an average of 15 seconds in a booth

In N booths , there will be N/15 vehicles in 1 second

In 1 hr, there will be N/15 * 3600 vehicles

Therefore, there will be a total of 240N vehicles/hour

Actual arrival rate of vehicles at the airport is 500 veh/h

Probability of arrival, P = \frac{Number of possible outcomes}{Total outcomes}

P = 500/240N

P = 2.083/N

For the average time spends to be below 5 seconds

\frac{(\frac{P^{2} }{1-p} )}{500} = 5, since 500 is the average value.

\frac{P^{2} }{1-p} } = 2500\\P^{2} = 2500 (1-P)\\P^{2} = 2500 - 2500P\\(\frac{2.083}{N}) ^{2} = 2500 - 2500(\frac{2.083}{N})

2.083^{2} = 2500N^{2} - 5208N\\2500N^{2} - 5208N - 4.34 = 0

N^{2} -2.0832N - 0.0017 = 0

Solving for N using the quadratic formula with a = 1, b = -2.0832, c = -0.0017

N = \frac{-b \pm \sqrt{b^{2} -4ac} }{2a} \\N = \frac{2.0832 \pm \sqrt{(-2.0832)^{2} -4*1*(-0.0017)} }{2}

N = 1.0416 ± 1.0424

N = 2.084 or -0.0008

N = 2.084 is the only realistic value here

Therefore, the smallest number of processing booths that must be open should be 3

5 0
2 years ago
A clock is constructed using a regular polygon with 60 sides. The polygon rotates every minute. How much has the polygon rotated
stepladder [879]

Answer:42°

Step-by-step explanation:So each minute, it advances by 1/60 of a complete rotation. A complete rotation is, of course, 360° . So each minute, it advances (360°/60) = 6° . (6° / minute) x (7 minutes) = 42°

3 0
3 years ago
Read 2 more answers
Simplify: -0.8b+4.1c-(-3.2b)-0.1c
BigorU [14]

[ Answer ]

\boxed{2.4b \ + \ 4c}

[ Explanation ]

  • Simplify: -0.8b + 4.1c - (-3.2b) - 0.1c

-----------------------------------

  • Apply Rule: - (-a) = a

-0.8b + 4.1c + 3.2b - 0.1c

  • Group Like Terms

-0.8b + 3.2b + 4.1c - 0.1c

  • Add Similar Elements: -0.8b + 3.2b = 2.4b

2.4b + 4.1c - 0.1c

  • Add Similar Elements: 4.1c - 0.1c = 4c

2.4b + 4c

\boxed{[ \ Eclipsed \ ]}

8 0
3 years ago
the sides of a rectangle are in the ratio 2:5. if the longer side of the rectangle is 25.5 in., what are it's width, perimeter,
Ad libitum [116K]

Answer: The width of the rectangle is 10.2 inches, the perimeter is 71.4 inches,  the area is 260.1 inches.

Step-by-step explanation:

25.5/5=5.1

5.1*2=10.2

The width is 10.2 inches

25.5*2+10.2*2=71.4

The perimeter is 71.4 inches

20.5*10.2=260.1

The area is 260.1

6 0
3 years ago
Describe the graph of y={1/(2x-10)}-3 compared to the graph of y=1/x
tester [92]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)=  A(  Bx+  C)+  D
\\\\
~~~~y=  A(  Bx+  C)+  D
\\\\
f(x)=  A\sqrt{  Bx+  C}+  D
\\\\
f(x)=  A(\mathbb{R})^{  Bx+  C}+  D
\\\\
f(x)=  A sin\left( B x+  C  \right)+  D
\\\\
--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\
\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }  B\textit{ is negative}

\bf ~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{  C}{  B}\\
~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }  D\\
~~~~~~if\   D\textit{ is negative, downwards}\\\\
~~~~~~if\   D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{  B}

with that template in mind, let's check these two

\bf \stackrel{parent}{y=\cfrac{1}{x}}\qquad \qquad\qquad \qquad  \stackrel{transformed}{y=\cfrac{1}{\stackrel{B}{2}x\stackrel{C}{-10}}\stackrel{D}{-3}}\\\\
-------------------------------\\\\
B=2\qquad \textit{shrinks horizontally by }\frac{1}{2}
\\\\\\
C=-10\qquad \cfrac{C}{B}=\cfrac{-10}{2}\implies -5\qquad \textit{horizontally right-shifted by }5
\\\\\\
D=-3\qquad \textit{vertically down-shifted by }3
7 0
3 years ago
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