Answer:
Step-by-step explanation:
2^0 is less than or equal to 1!, because 1<= 1
if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since
(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0
Answer: Two and one tenth.
R^2/2(pi/180*D-sin(D)) is the formula so 6^2/2(pi/180*120-sin(120)) is the problem which comes to about 22cm^2
158.71 rounded to the nearest ten dollars would be $160.00
then to estimate 10% since 10% starts with a 1, just remove the zero from both numbers
so 160 becomes 16
the tip would be $16
You would pay $240 per year, hope this helps
