Answer:
The point for the given linear equations is (
, 
)
Step-by-step explanation:
Given as :
The two linear equations are
First equation
y = 
x + 5
Or, y + x + 5 = 0
Taking LCM we get
y + x + 10 = 0 .......1
Second equation
y = 2 x + 2 ........2
Now solving both equation
Putting the value of y from eq 2 into eq 1
(2 x + 2) + x + 10 = 0
Or, 3 x + 12 = 10
Or, 3 x = 10 - 12
Or, 3 x = - 2
∴ x =
Now putting the value of x into eq 2
∵ y = 2 x + 2
Or, y = 2 × + 2
Or, y = 
+ 2
Or, y = 
∴ y =
So, The points are (x , y ) = ( , )
Now, plotting the points on x-y coordinate graph
Hence, The point for the given linear equations is ( , ) Answer
Answer:y = 2x + 4
Explanation:
1) The slope - intercept form is of the kind y = mx + b, where m is the slope and b is the y-intercept.
2) Given two points you can find the slope (using the two points) and then the equation using one of the points.
3) slope = m = Δy / Δx
points given (3,10) , (0,4)
m = [y2 - y1] / [x2 - x1] = [10 - 4] / [3 - 0] = 6 / 3 = 2
4) equation
y - y2
-------- = m
x - x2
y - 4
---------- = 2
x - 0
=> y - 4 = 2 (x - 0)
y - 4 = 2x
y = 2x + 4
Answer:
The dimension of the plot is 30 yd by 20 yd
Step-by-step explanation:
Given;
Area = 600 yd^2
Length = width + 10
l = w + 10 ......1
Area of a rectangular plot is;
Area A = length × width
A = l × w
Substituting equation 1;
A = (w+10) × w
A = w^2 + 10w
600 = w^2 + 10w
w^2 +10w -600 = 0
Solving the quadratic equation;
w = -30 or 20
cannot be negative
w = 20 yd
l = w+10 = 20+10 = 30yd
The dimension of the plot is 30 yd by 20 yd
That would be -2 1/2 , 3 1/2
Answer:
b=15
How I got it:
32 + (7x4) = 32 + 28 = 60
60 divided by 4 = 15
Checking:
15 - 7 = 8
8 x 4 = 32
32 = 32
<em>You can tell b = 15 is the correct answer.</em>
