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vfiekz [6]
4 years ago
12

Factories (a+b)^3+8c^3​

Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0

Answer:

(a + b + 2c)(a² + 2ab + b² - 2ac - 2bc + 4c²)

Step-by-step explanation:

Given

(a + b)³ + 8c³ ← this is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²)

Thus

(a + b)³ + 8c³

= (a + b)³ + (2c)³

= (a + b + 2c)( (a + b)² - 2c(a + b) + (2c)² )

= (a + b + 2c)(a² + 2ab + b² - 2ac - 2bc + 4c²)

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Please help me 30 points please help me
Romashka [77]

Answer:

y = + 1x - 4y

Step-by-step explanation:

This could be the wrong way of writing it but thats the pattern ❤

4 0
3 years ago
Factorise completely:<br> 1. 3xy - x<br>2. 4a² - 9​
Amanda [17]

Answer:

x(3y - 1) and (2a - 3)(2a + 3)

Step-by-step explanation:

(1)

3xy - x ← factor out x from each term

= x(3y - 1)

(2)

4a² - 9 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - 9

= (2a)² - 3²

= (2a - 3)(2a + 3)

6 0
2 years ago
Find the cosine of angle A to the nearest 100th.
Sauron [17]

Answer:

{ \tt{ \cos(A) =  \frac{ \sqrt{700} }{40}  }} \\  { \tt{ \cos(A) = 0.66 }}

4 0
3 years ago
Use the tests for divisibility to determine which numbers divide evenly into the given number.
drek231 [11]

The numbers that can divide 648 evenly, using the divisibility tests, include <u>1, 2, 3, 4, 6, 8, 9, 12, and 18</u> and some multiples of any two numbers.

<h3>What is the divisibility test?</h3>

A divisibility test is performed to identify whether a number can be divided evenly by a fixed divisor without a remainder and without actually performing the division process.

<u>Divisibility by 1</u>: Every number is divisible by 1 = 648 (648/1).

<u>Divisibility by 2</u>: 648 is an even number and divisible by 2 = 324.

<u>Divisibility by 3</u>: Sum the digits (18). 18 is divisible by 3 = 6 (18/3).

<u>Divisibility by 4</u>: The last two digits (4 and 8) form a number (12) that is divisible by 4

<u>Divisibility by 6</u>:  It is divisible by 2 and by 3

<u>Divisibility by 8</u>: If the hundreds digit is even, the number formed by the last two digits must be divisible by 8.

<u>Divisibility by 9</u>: Sum the digits (18). 18 is divisible by 9

<u>Divisibility by 12</u>: 648 is divisible by 3 and by 4.

<u>Divisibility by 18</u>: 648 is divisible by 2 and by 9.

Learn more about the divisibility tests at brainly.com/question/24125354

#SPJ1

5 0
2 years ago
Which equation does not represent a quadratic function?
Kryger [21]

\text{A quadratic function is in the  form of } ~ f(x)=ax^2 +bx+c.\\\\\\y=x+5 ~ \text{is linear so it is not in a form of quadratic function.}

3 0
3 years ago
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