3 years ago

Factories (a+b)^3+8c^3

1 answer:

8 0

Answer:

(a + b + 2c)(a² + 2ab + b² - 2ac - 2bc + 4c²)

Step-by-step explanation:

Given

(a + b)³ + 8c³ ← this is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²)

Thus

(a + b)³ + 8c³

= (a + b)³ + (2c)³

= (a + b + 2c)( (a + b)² - 2c(a + b) + (2c)² )

= (a + b + 2c)(a² + 2ab + b² - 2ac - 2bc + 4c²)

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