Answer:
Hope this helped :)
Step-by-step explanation:
Convection flows structure in light of the fact that a warmed liquid grows, getting less thick. The less-thick warmed liquid ascents from the warmth source. ... For example, a hot radiator warms the air promptly around it. The air ascends toward the roof, pulling cooler air down from the roof into the radiator to be warmed.
Answer: Clean
Explanation:
Adjectives are words that describes nouns. Therefore, clean is an adjective.
16x + 33y = 260, I think this is correct. Hope this helps!:)
Answer:
7/24
Step-by-step explanation:
you have to have a common denominator so you multiply one denominator to the opposite numerator and denominator and vice versa. So for 2/3 you should get 16/24 and for 3/8 you should get 9/24. Then you subtract 9 from 16 and get 7. So the answer is 7/24
Answer:
a) For the 90% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of and , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of and , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
