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gregori [183]
3 years ago
7

In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=83°, and RS = 7 feet. Find the length of SQ to the nearest tenth of a foot.

Mathematics
2 answers:
Marrrta [24]3 years ago
8 0

Answer: 0.9

Step-by-step explanation:

Nadusha1986 [10]3 years ago
6 0

Answer:

Step-by-step explanation

….

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Please help!!!!!!!!!!!!!!
Aloiza [94]

Answer:

11.4 feet

Step-by-step explanation:

Using the right triangle formed by the tent pole, the ground and the guy rope,  where the guy rope (g) is the hypotenuse.

Applying Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

g² = 9² + 7² = 81 + 49 = 130 ( take the square root of both sides )

g = \sqrt{130} ≈ 11.4 feet

7 0
3 years ago
This as a decimal 6th​
makkiz [27]

Answer:

the answer to the question is 3.2

8 0
3 years ago
Question 2
evablogger [386]

The domain of the function is x ≤ 6.88

The domain of the function is y ≤ 20

<h3>Domain and Range</h3>
  • These are input and output values for which the function exists

Given the function of x expressed as:

y = 3.5x + 2.8

The domain occurs at the point where 3.5x + 2.8 ≤ 20

3.5x ≤ 20 - 2.8

3.5x ≤ 17.2

x ≤ 6.88 - Domain

This given the domain of the function.

The range of the function is the point where y ≤ 20

Learn more on domain and range here: brainly.com/question/2264373

7 0
2 years ago
HURRY WILL MARK YOU BRAINLIEST RIGHT ANSWER ONLY
Galina-37 [17]

Answer:

Step-by-step explanation:

set the two equations equal to each other then solve for n

6n + 3 = 4n + 11

2n = 8

n = 4

plug n in for both equations

6(4) + 3

24 + 3 = 27

4(4) + 11

16 + 11 = 27

27 + 27 = 54

the distance is 54

8 0
3 years ago
Write the slope intercept form of the equation of the line through the given points x intercept of -5 and y intercept of -1. Pls
soldier1979 [14.2K]

bearing in mind that an x-intercept is when the graph touches the x-axis and when that happens y = 0, and a y-intercept is  when the graph touches the y-axis and when that happens x = 0.

\bf \underset{x-intercept}{(\stackrel{x_1}{-5}~,~\stackrel{y_1}{0})}\qquad \underset{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-5)}}}\implies \cfrac{-1}{0+5}\implies -\cfrac{1}{5}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{1}{5}}[x-\stackrel{x_1}{(-5)}] \\\\\\ y=-\cfrac{1}{5}(x+5)\implies y = -\cfrac{1}{5}x-1

4 0
3 years ago
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