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ivanzaharov [21]
3 years ago
11

Nhich expression has the least value when x=50? 1/x 10/x 10-x 1-x

Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

1-x

Step-by-step explanation:

1/50= 0.02

10/50= 0.2

10-50= -40

1-50= -49

-49 has the lowest value of all of these equations.

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Solve the equation y. 6=2(y+2)
atroni [7]

Answer:

y = 1

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    6-(2*(y+2))=0

Step by step solution :

Equation at the end of step  1  :

 6 -  2 • (y + 2)  = 0

Pulling out like terms :

3.1     Pull out like factors :

  2 - 2y  =   -2 • (y - 1)

Equation at the end of step  3  :

 -2 • (y - 1)  = 0

Equations which are never true :

4.1      Solve :    -2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2      Solve  :    y-1 = 0

Add  1  to both sides of the equation :

                     y = 1

One solution was found :

                  y = 1

Processing ends successfully

plz mark me as brainliest :)

6 0
3 years ago
Read 2 more answers
a solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned
Jlenok [28]

Question:

A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .

(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d

(b) How much of excess will be left after one month (1 month = 30 days)

Answer:

a. E = 6500 - 50d

b. E = 5000

Step-by-step explanation:

Given

Excess = 6500kwh

Rate = 50kwh/day

Solving (a): E in terms of d

The Excess left (E) in d days is calculated using:

E = Excess - Rate * days

The expression uses minus because there's a reduction in the excess kwh on a daily basis.

Substitute values for Excess, Rate and days

E = 6500 - 50 * d

E = 6500 - 50d

Solving (b); The value of E when d = 30.

Substitute 30 for d in E = 6500 - 50d

E = 6500 - 50 * 30

E = 6500 - 1500

E = 5000

<em>Hence, there are 5000kwh left after 30 days</em>

4 0
3 years ago
What is the equation for the line in the slope intercept form enter your answer in the box ​
Hoochie [10]

Answer:

i belive it is y=-4x+5

Step-by-step explanation:

i just did the test

6 0
3 years ago
A horse takes 3 steps to walk the same distance for which a goat takes 4 steps. Suppose 1 step of the dog covers 1/2 of a metre.
almond37 [142]

Answer:

The goat would cover <u>9 meters</u> in taking 24 steps.

Step-by-step explanation:

<u><em>There is a mistake in the question so the correct question is below:</em></u>

A horse takes 3 steps to walk the same distance for which a goat takes 4 steps. Suppose 1 step of the horse covers 1/2 of a metre. How many metres would the goat cover in taking 24 steps?

Now, to find the meters goat cover in taking 24 steps.

As 1 step of horse covers =  \frac{1}{2} \ meter.

So, 3 step of horse covers = \frac{1}{2} \times 3 =\frac{3}{2} =1.5\ meters.

<u><em>Thus, 3 steps of horse covers = 1.5 meter</em></u><em>s.</em>

<em>As given, the horse takes 3 steps to walk the same distance for which a goat takes 4 steps.</em>

<u><em>So, the distance covers by goat in 4 steps = 1.5 meters.</em></u>

Now, to get the meters goat cover in taking 24 steps by using unitary method:

If, the distance cover by the goat in 4 steps = 1.5 meters

So, the distance cover by the goat in 1 step = \frac{1.5}{4}

Thus, the distance cover by the goat in 24 steps = \frac{1.5}{4}\times 24

= \frac{36}{3}

= 9\ meters.

Therefore, the goat would cover 9 meters in taking 24 steps.

8 0
3 years ago
Graph this please due today
vaieri [72.5K]

Answer: see last picture

Step-by-step explanation:

We see that the y-intercept is 10 and the slope is -3

so when x = 0, y = 10

Graph this first point (picture 1)

Since the slope is -3, every time you go one unit to the left, you go down 3 units, so graph this second point (picture 2)

Continue this until you have no more room on the graph (picture 3)

now draw a line through the dots (picture 4)

4 0
4 years ago
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