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4 years ago

HJ= 5x -3, JK= 8x -9 and KH= 131

Mathematics

1 answer:

Fynjy0 [20]4 years ago

6 0

Answer:

HJ = 52

JK = 79

Step-by-step explanation:

Hello, I want to assume you are trying to determine either HJ or JK. Below is an illustration of how to determine either HJ or JK.

From the question given above, the following data were obtained:

HJ = 5x – 3

JK = 8x – 9

KH = 131

If we draw a straight line, we'll observe the following:

H_______J_______K

KH = HJ + JK

Next, we shall determine the value of x.

HJ = 5x – 3

JK = 8x – 9

KH = 131

KH = HJ + JK

131 = (5x – 3) + (8x – 9)

131 = 5x – 3 + 8x – 9

Collect like terms

131 + 3 + 9 = 5x + 8x

143 = 13x

Divide both side by 13

x = 143 / 13

x = 11

Finally, we shall determine HJ and JK. This can be obtained as follow:

For HJ:

HJ = 5x – 3

x = 11

HJ = 5(11) – 3

HJ = 55 – 3

HJ = 52

For JK:

JK = 8x – 9

x = 11

JK = 8x – 9

JK = 8(11) – 9

JK = 88 – 9

JK = 79

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Answer:

$y=3.53 x +37.92$

And for 0 miles if we use the model we got:

$y(0)= 3.53*0 +37.92 = 37.92$

But for this case. No is not reasonable for a representative to travel o miles and have a positive amount of sales.

Step-by-step explanation:

For this case we assume the following data:

Miles traveled (X): 2,3,10,7,8,15,3,1,11

Sales (Y): 31,33,78,62,65,61,48,55,120

We want to found a linear model like this one : $y = mx+b$ . Where:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=582-\frac{60^2}{9}=182$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=4329-\frac{60*553}{9}=642.33$

And the slope would be:

$m=\frac{642.33}{182}=3.529$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{60}{9}=6.667$

$\bar y= \frac{\sum y_i}{n}=\frac{553}{9}=61.444$

And we can find the intercept using this:

$b=\bar y -m \bar x=61.444-(3.529*6.667)=37.917$

So the line would be given by:

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And for 0 miles if we use the model we got:

$y(0)= 3.53*0 +37.92 = 37.92$

But for this case. No is not reasonable for a representative to travel o miles and have a positive amount of sales.

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