y-y1 x-x1 -------- = ------- y2-y1 x2-x1
y-(-5) x-1 ------- = ---- 7-(-5) -3-1
y+5*(-4)=12*(x-1) -4y-20=12x-12 12x+4y+8=0 /4 3x+y+2=0
why: To form an linear equation for a line, you must remember 2 things
****First find its gradient, second, find the y-intercept.
General equation for a line: y = mx + c, where m = gradient, and c = y-intercept.
Gradient, m = {7 - (-5)} / {(-3) - 1} = - 3
To find the y-intercept, you must use one of the point (-3, 7) or (1, -5) and substitute the value of x and y from the coordinate u choose into the general equation y = mx + c.
I choose (1, -5), so -5 = -3(1) + c -5 = -3 + c -5 + 3 = c -2 = c
Thus,
the equation in slope-intercept form is y = -3x - 2.
the equation in standard form is y + 3x + 2 = 0
the equation in point-slope form is y + 3x = -2 divide both sides with -2 y / (-2) + 3x / (-2) = -2 / -2 - y / 2 - x / (2/3) = 1
3(9)-2
27-2
25
25 is your answer
I believe the correct situation is C
Answer:
x = -5
Step-by-step explanation:
-(5x-2) = 27
Distribute the minus sign
-5x +2 = 27
Subtract 2 from each side
-5x +2-2 = 27-2
-5x = 25
Divide by -5
-5x/-5 = 25/-5
x = -5
It has to be at lest 9u2-4?