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Evgen [1.6K]
2 years ago
6

Carlos went to gas station A and paid $54 for 25 gallons. Sasha went to gas

Mathematics
1 answer:
RideAnS [48]2 years ago
5 0

Answer: Sasha

Step-by-step explanation:

carlos- 54 divided by 25 equals 2.25 dollars for each gallon

sasha- 31.25 divided by 15 equals 2.083333(3 repeats)

They are both really close on price, but sasha's is cheaper

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In supply (and demand) problems, y is the number of items the supplier will produce (or the public will buy) if the price of the
SSSSS [86.1K]

Answer:

A) (17 ; 550)

B) $17/item

C) 550

Step-by-step explanation:

First we must calculate the intersection point of the two lines. Since in that point <em>y</em> has the same value in both equations, we can obtain <em>x </em>by equalling the two equations and then using that value for obtaining <em>y</em>:

5x+465=-6x+652\\5x+6x=652-465\\11x=187\\x=\frac{187}{11}\\x=17

So the value of <em>x</em> in the intersection point is 17. We now use this value with either one of the equations to obtain <em>y</em><em>. </em>Let's use the supply equation:

y=5*17+465\\y=550

So the intersection point is (17 ; 550)

Supply and demand are in equilibrium when the amount of items on supply are the same as the ones on demand. That is the point were the two lines intersect, which means the selling price is the <em>x</em> coordinate and the amount of items is the <em>y</em> coordinate, so that is a selling price of <em>$17/item</em> with a number of items of <em>550</em>.

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15 points Need ASAP- Use the table to write a proportion ~ (table on picture)
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Step-by-step explanation:

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Read 2 more answers
第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows
tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

P(A/B)=\frac{P(A)*P(B/A)}{P(B)}

let A be the  event that the student knows the answer .

B be  the  event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}

Probability that the answer is correct ,given that he knows the answer is

P(E/A)=1

Probability that the answer is correct ,given that he guesses it is

P(E/B)=\frac{1}{3}   [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}

Substituting the values we get

P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }

=\frac{6}{30}*\frac{30}{18}  \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}

Therefore ,  the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

8 0
8 months ago
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