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3 years ago

Which part of the eye controls whether or not the pupil dilates or constricts? iris retina optic nerve cornea

Physics

2 answers:

Bas_tet [7]3 years ago

6 0

The answer is Iris (i just took the quiz)

VashaNatasha [74]3 years ago

3 0

Answer:

A. Iris

Explanation:

I took the quiz :)

k12, 8th grade

Good luck deary...

<3

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A busy waitress slides a plate of apple pie along a counter to a hungry customer sitting near the

Ostrovityanka [42]

Answer:

a. 0.5307 sec

b. 0.4458 m

c. = $v_x=0.84\ m/s\ ,\ v_y=5.2\ m/s$

Explanation:

Horizontal Motion

It describes the dynamics of an object thrown horizontally in free air. The initial horizontal velocity is maintained all the time since no horizontal forces are acting. The initial vertical velocity is zero at launch time, but it grows downwards powered by the acceleration of gravity.

The object hits the ground at a distance x from the point of launching, after having traveled a vertical distance $y_o$ , taking a time t to complete the travel. The formulas who relate the different magnitudes are

$v_x=v_o$

The horizontal velocity $v_x$ is the same regardless of the elapsed time

$v_y=gt$

$x=v_ot$

$\displaystyle y=y_o-\frac{gt^2}{2}$

The plate of apple pie left the counter at a speed

$v_o=0.84\ m/s$

The counter is $y_o=1.38\ m$ high.

Knowing that

$y_o=1.38\ m$

We use this formula to compute t

$\displaystyle y=y_o-\frac{gt^2}{2}$

At the moment when the plate hits the floor y=0

$\displaystyle 0=y_o-\frac{gt^2}{2}$

$\displaystyle y_o=\frac{gt^2}{2}$

Solving for t

$\displaystyle t=\sqrt{\frac{2y_o}{g}}$

$\displaystyle t=\sqrt{\frac{2(1.38)}{9.8}}$

$t=0.5307\ sec$

$x=(0.84)(0.5307)$

$x=0.4458\ m$

$v_x=0.84\ m/s$

$v_y=(9.8)(0.5307)$

$v_y=5.2\ m/s$

3 0

4 years ago

A car is traveling with constant velocity. this means that _______.

Lilit [14]

It is traveling in a straight line and its speed is not changing

7 0

3 years ago

2. Two projectiles thrown from the same point at angles 0,=60° and 02=30° with the horizontal,

Liono4ka [1.6K]

Answer:

The answer is below

Explanation:

The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:

$h=\frac{u^2sin^2\theta}{2g}$

Given that the two projectile has the same height.

$For\ the\ first\ projectile\ with\ an\ angle\ \60^0 \ with\ the\ horizontal\ and initial\ velocity\ u_1:\\\\h=\frac{u_1^2sin^260}{2g} =\frac{0.75u_1^2}{2g} \\\\For\ the\ second\ projectile\ with\ an\ angle\ \30 \ with\ the\ horizontal\ and initial\ velocity\ u_2:\\\\h=\frac{u_2^2sin^230}{2g} =\frac{0.25u_2^2}{2g}\\\\\frac{0.25u_2^2}{2g}=\frac{0.75u_1^2}{2g}\\\\0.25u_2^2=0.75u_1^2\\\\\frac{u_1^2}{u_2^2} =\frac{0.25}{0.75} \\\\\frac{u_1^2}{u_2^2}=\frac{1}{3} \\$ $\\\frac{u_1}{u_2}=\sqrt\frac{1}{3}$

8 0

3 years ago

The Sun delivers an average power of 1150 W/m2 to the top of the Earth’s atmosphere. The permeability of free space is 4π × 10−7

My name is Ann [436]

Answer:

E=930.84 N/C

Explanation:

Given that

I = 1150 W/m²

μ = 4Π x 10⁻⁷

C = 2.999 x 10⁸ m/s

E= C B

C=speed of light

B=Magnetic filed ,E=Electric filed

Power P = I A

A=Area=4πr² ,I=Intensity

$I=\dfrac{CB^2}{2\mu_0}$

$I=\dfrac{CE^2}{2\mu_0 C^2}$

$E=\sqrt{{2I\mu_0 C}}$

$E=\sqrt{{2\times 1150\times 4\pi \times 10^{-7}(2.99792\times 10^8)}}$

E=930.84 N/C

Therefore answer is 930.84 N/C

4 0

3 years ago

Which of the following is true of greenhouse gases?

Sedaia [141]

Answer:

A. They trap energy in the atmosphere.

Explanation:

Greenhouse gases are defined as gases that absorb and emit radiation within the infrared range. These gases allow the sun’s rays to pass through the ozone layer and warm the earth, but prevent this warmth from escaping atmosphere.

Greenhouse gases cause the greenhouse effect on planets. Examples of greenhouse gases in Earth's atmosphere are water vapor, carbon dioxide, methane, ozone etc.

4 0

3 years ago