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Varvara68 [4.7K]
3 years ago
5

The Sun delivers an average power of 1150 W/m2 to the top of the Earth’s atmosphere. The permeability of free space is 4π × 10−7

T · N/A and the speed of light is 2.99792 × 108 m/s. Find the magnitude of Em for the electromagnetic waves at the top of the atmosphere. Answer in units of N/C.
Physics
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

E=930.84 N/C

Explanation:

Given that

I = 1150 W/m²

μ = 4Π x 10⁻⁷

C = 2.999 x 10⁸ m/s

E= C B

C=speed of light

B=Magnetic filed  ,E=Electric filed

Power  P = I A

A=Area=4πr²  ,I=Intensity

I=\dfrac{CB^2}{2\mu_0}

I=\dfrac{CE^2}{2\mu_0 C^2}

E=\sqrt{{2I\mu_0 C}}

E=\sqrt{{2\times 1150\times 4\pi \times 10^{-7}(2.99792\times 10^8)}}

E=930.84 N/C

Therefore answer is 930.84 N/C

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Answer:

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Explanation:

Force on electron = E e where E is electric field and e is charge on electron

acceleration generated = Ee / m where m is mass of the electron .

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Answer:

Explanation:

Givens

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Q=m C_s \Delta T
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