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natima [27]
3 years ago
12

3. (04.02 MC) Which component is missing from the process of photosynthesis? Carbon Dioxide + Water + ________ Glucose + Oxygen

Chemistry
1 answer:
IgorLugansk [536]3 years ago
6 0

Answer:

Sunlight

Explanation:

Sunlight is always neccesary in photosynthesis

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Why do elements have different<br> properties?
Ann [662]
I think because each element has its own number of protons and neutrons, giving it its own atomic number and mass (correct me if I’m wrong please)
3 0
3 years ago
3AsBr3 how many atoms
Artyom0805 [142]

Answer:

there are 18

Explanation:

3 0
3 years ago
Enthalpy of formation (kJ/mol) C6H12O6(s)-1260 O2 (g)0 CO2 (g)-393.5 H2O (l)-285.8 Calculate the enthalpy of combustion per mole
trapecia [35]

Answer : The enthalpy of combustion per mole of C_6H_{12}O_6 is -2815.8 kJ/mol

Explanation :

Enthalpy change : It is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]

The equilibrium reaction follows:

C_6H_{12}O_6(s)+6O_2(g)\rightleftharpoons 6CO_2(g)+6H_2O(l)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(n_{(CO_2)}\times \Delta H^o_f_{(CO_2)})+(n_{(H_2O)}\times \Delta H^o_f_{(H_2O)})]-[(n_{(C_6H_{12}O_6)}\times \Delta H^o_f_{(C_6H_{12}O_6)})+(n_{(O_2)}\times \Delta H^o_f_{(O_2)})]

We are given:

\Delta H^o_f_{(C_6H_{12}O_6(s))}=-1260kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(6\times -393.5)+(6\times -285.8)]-[(1\times -1260)+(6\times 0)]=-2815.8kJ/mol

Therefore, the enthalpy of combustion per mole of C_6H_{12}O_6 is -2815.8 kJ/mol

6 0
4 years ago
Read 2 more answers
Help plz already know 1&amp;2
Aleonysh [2.5K]
3. A
4. B
5. A
6. E
7. A
8. C
9. A
10. B
Some of these were guesses but they were educated guesses. Best of luck. If some of them are wrong I am sorry.  <span />
3 0
3 years ago
What is the molarity of a solution with a volume of 974 mL containing 17 g of CuSO4
liberstina [14]

Answer : The correct option is, (A) 0.109 M CuSO_4

Solution : Given,

Mass of CuSO_4 = 17 g

volume of solution = 974 ml

Molar mass of CuSO_4 = 159.609 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

Molarity=\frac{w\times 1000}{M\times V_s}

where,

w = mass of CuSO_4 (solute)

M = molar mass of CuSO_4

V_s = volume of solution in liter

Now put all the given values in the above formula, we get the molarity of solution.

Molarity=\frac{(17g)\times 1000}{(159.609g/mole)\times (974ml)}=0.109mole/L=0.109M

Therefore, the molarity of the solution is, 0.109 M

5 0
4 years ago
Read 2 more answers
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