Answer:
B.3/5p
Explanation:
For this question, we have to remember <u>"Dalton's Law of Partial Pressures"</u>. This law says that the pressure of the mixture would be equal to the sum of the partial pressure of each gas.
Additionally, we have a <em>proportional relationship between moles and pressure</em>. In other words, more moles indicate more pressure and vice-versa.
Where:
=Partial pressure
=Total pressure
=mole fraction
With this in mind, we can work with the moles of each compound if we want to analyze the pressure. With the molar mass of each compound we can calculate the moles:
<u>moles of hydrogen gas</u>
The molar mass of hydrogen gas (
) is 2 g/mol, so:
<u>moles of oxygen gas</u>
The molar mass of oxygen gas (
) is 32 g/mol, so:
Now, total moles are:
Total moles = 2 + 3 = 5
With this value, we can write the partial pressure expression for each gas:
So, the answer would be <u>3/5P</u>.
I hope it helps!
Answer:
F = ma or Force = mass x acceleration.
Explanation:
Newtons second law is about the force put onto an object. To find this you would use the formula:
Force is equal to mass times acceleration (F=ma)
Carbon disulfide ( S=C=S) is made up of one carbon atom and two sulfur atom.
Carbon has 4 valence electrons while sulfur has 6 electrons.
During bonding all the four carbon valence electrons are used in bonding while each sulfur atom contributes two electrons two the bond formation.
Therefore; 4 + 2(2) = 8 electrons are used for bonding, while 8 electrons ( four from each sulfur atom) are not used for bond formation.
Answer:
0.44 L.
Explanation:
Density of nickel(II) chloride = 29.8 g/dL.
Mass of nickel(II) chloride = 131 g
Volume of nickel(II) chloride =?
Next, we shall convert 29.8 g/dL to g/L. This can be obtained as follow:
Recall:
1 g/dL = 10 g/L
Therefore,
29.8 g/dL = 29.8 x 10 = 298 g/L
Therefore, 29.8 g/dL is equivalent to 298 g/L.
Finally, we shall determine the volume of nickel(II) chloride as follow:
Density of nickel(II) chloride = 298 g/L
Mass of nickel(II) chloride = 131 g
Volume of nickel(II) chloride =?
Density = mass /volume
298 = 131/Volume
Cross multiply
298 x Volume = 131
Divide both side by 298
Volume = 131/298
Volume = 0.44 L
Therefore, the volume of of nickel(II) chloride is 0.44 L
