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3 years ago

15

imagine that you're able to fully dissolve a powered substance and water what can be said about this creation

1 answer:

Softa [21]3 years ago

8 0

We can say that the water is the solvent, and the powder is the solute. This is also a solution altogether.

Explanation:- A solute is the thing being dissolved into the solvent. While the solvent is what when the solute is being dissolved in. Together, they make a solution.

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natali 33 [55]

Answer:

The following formula is used to calculate the speed or velocity of a wave. V = f * w Where V is the velocity (m/s) f is the frequency (hz)

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2 years ago

PLEASE HELP ME YOU DONT HAVE TO DO WORK JUST TELL ME IF ITS RIGHT ON THE ORGANIC AND INORGANIC SIDE PLEASEE

Fittoniya [83]

Answer:

Its right you dont have to change anything

3 0

3 years ago

Use the equation n2 + 3h2=2nh3 if 8.0g N2 react, how many grams of NH3 will be produced

Eduardwww [97]

the balanced equation for the formation of ammonia is

N₂ + 3H₂ ---> 2NH₃

molar ratio of N₂ to NH₃ is 1:2

mass of N₂ reacted is 8.0 g

therefore number of N₂ moles reacted is - 8.0 g / 28 g/mol = 0.286 mol

according to the molar ratio,

1 mol of N₂ will react to give 2 mol of NH₃, assuming nitrogen is the limiting reactant

therefore 0.286 mol of N₂ should give - 2 x 0.286 mol = 0.572 mol of NH₃

therefore mass of NH₃ formed is - 0.572 mol x 17 g/mol = 9.72 g

a mass of 9.72 mol of NH₃ is formed

6 0

3 years ago

What is 4.07 cm x 2.3cm, rounded to the correct number of significant figures

Tom [10]

Answer: 9.4cm^2

Explanation:

8 0

3 years ago

A cylinder with a moveable piston contains 92g of Nitrogen. The external pressure is constant at 1.00 atm. The initial temperatu

Jobisdone [24]

Answer:

Work done in this process = 4053 J

Explanation:

Mass of the gas = 0.092 kg

Pressure is constant = 1 atm = 101325 pa

Initial temperature $T_{1}$ = 200 K

Final temperature $T_{2}$ = 200 - 85 = 115 K

Gas constant for nitrogen = 297 $\frac{J}{kg k}$

When pressure of a gas is constant, volume of the gas is directly proportional to its temperature.

⇒ V ∝ T

⇒ $\frac{V_{2} }{V_{1} }$ = $\frac{T_{2} }{T_{1} }$ ------------ ( 1 )

From ideal gas equation $P_{1}$ $V_{1}$ = m R $T_{1}$ ------ (2)

⇒ 101325 × $V_{1}$ = 0.092 × 297 × 200

⇒ $V_{1}$ = 0.054 $m^{3}$

This is the volume at initial condition.

From equation 1

⇒ $\frac{V_{2} }{0.054}$ = $\frac{200}{115}$

⇒ $V_{2}$ = 0.094 $m^{3}$

This is the volume at final condition.

Thus the work done is given by W = P [ $V_{2}$ - $V_{1}$ ]

⇒ W = 101325 × [ 0.094 - 0.054]

⇒ W = 4053 J

This is the work done in that process.

7 0

3 years ago