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lutik1710 [3]
2 years ago
11

I need to find the slope and b Y=mx+b HELP ME

Mathematics
1 answer:
Naddika [18.5K]2 years ago
7 0

Answer:

y=-\frac{4}{3}x+20

Step-by-step explanation:

stupid enough

y=mx+b

\frac{y1-y2}{x1-x2}

slope = 16-12/3-6

-4/3

y=-\frac{4}{3}x+b

plug in x and y

16=-4/3(3)+b

b=20

<h2><em><u>Red</u></em></h2>
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<em>Using the formulas</em>

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<em>d = C</em>

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2 years ago
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4 0
3 years ago
Read 2 more answers
Find all angles, 0≤θ&lt;360, that satisfy the equation below, to the nearest 10th of a degree. 4tan^2 θ+tanθ=−4tanθ−1
Serga [27]

Answer:

135 and 315degrees

Step-by-step explanation:

Given the expression

4tan²θ+tanθ=−4tanθ−1

Equate to zero

4tan²θ+tanθ+4tanθ+1 = 0

4tan²θ+5tanθ+1 = 0

Let x = tanθ

4x²+5x+1 = 0

Factorize;

4x²+4x+x+1 = 0

4x(x+1)+1(x+1) = 0

4x+1 = 0 and x+1 = 0

4x = -1 and x = -1

x = -1/4 and -1

Since x = tanθ

-1 =tanθ

θ = arctan(-1)

θ = -45degrees

Since tan is negative in the 2nd and fourth quadrant;

In the second quadrant

θ = 180 - 45 = 135degrees

In the fourth quadrant;

θ = 360 - 45 = 315degrees

Hence the required angles are 135 and 315degrees

3 0
3 years ago
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