Answer:
Step-by-step explanation:
Hope this helps you
Find the locus of a point P such that its ordinate is equal to the abscissa. Hence required equation of the locus of point P is y = 5x + 9. Hence required equation of the locus of point P is x = 2y + 3.
Answer:
2(3 + 8k)
Step-by-step explanation:
given : 6+16k
note that the GCF of 6 and 16 is 2, hence we can factor 2 out of the expression
6+16k
= (2)(3) + (2)(8k)
= 2(3 + 8k)
The domain is (0,-5) and range is (0,-7) the y is the range and the x is the domain
F(x) and g(x) were inverse functions, then if f(a) = b, then g(b) = a
f(x) = (5x+1) / x g(x) = x / (5x+1)
f(1) = 6, but g(6) = 6/31 ≠ 1
So, f(x) and g(x) are NOT inverse functions.
