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nignag [31]
3 years ago
14

How would you write out "The quotient of a number decreased by 7 and -2 is -10"

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

40

Step-by-step explanation:

The quotient of a number and six 7. n. + 4. Seven divided by a number, plus four. A number decreased by forty.

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If 18 is more than 2 times a number is -10, what is the number
AleksAgata [21]

Answer:

-14

Step-by-step explanation:

-10-18=-28 -28/2=-14

7 0
3 years ago
Do A triangle with sides measuring 12, 16, and 20 is a right triangle?
Julli [10]
Yes, because :
{16}^{2}  + {12}^{2}  \\  = \sqrt{400}  \\  = 20
4 0
3 years ago
Factor out the coefficient of the variable 5/6s+4/6
nirvana33 [79]
Okie, we find out the coefficient
5/6 s+ 4/6= 1/6 x 5s+ 1/6 x 4= 1/6(5s+4)

we have done this
Have a good day
5 0
3 years ago
COULD SOMONE PLZ PLZ HELP ME WITH THIS PROBLEM!!!
Jlenok [28]
1.b 2.a lines are parallel hope this helps =3

6 0
3 years ago
A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9
geniusboy [140]

Answer:

7.7 km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of 6.6 km and 3.9 km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, a^{2}+b^{2} =c^{2}, where a and b are the lengths of the triangle's legs and c is the length of the triangle's hypotenuse. In this case, we know what a and b are, and we need to solve for c, so after substituting the given values of a and b into a^{2}+b^{2} =c^{2} to solve for c, we get:

a^{2}+b^{2} =c^{2}

6.6^{2} +3.9^{2} =c^{2} (Substitute a=6.6 and b=3.9 into the equation)

43.56+15.21=c^{2} (Evaluate the squares on the LHS)

58.77=c^{2} (Simplify the LHS)

c^{2}=58.77 (Symmetric Property of Equality)

\sqrt{c^{2} } =\sqrt{58.77} (Take the square root of both sides of the equation)

c=7.7,c=-7.7 (Simplify)

c=-7.7 is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately 7.7 km away from its base. Hope this helps!

7 0
3 years ago
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