Answer:True
Step-by-step explanation:Empirical generalisation is the relationship between two variables that has been observed over a long period of time, science tries to show the interactions taking place between empirical Generalisation and theory,empirical Generalizations can also be seen as a pattern that repeats over different circumstances. Empirical Generalizations can also be said to be a reasoning from large example to basic conclusions which can be represented mathematically graphically or symbolically.
If О is the center of a circle then:
<span>
OA = OB = OC = OD [radii]
AB = AH + HB = 15 + 15 = 30 </span>⇒ AB = CD
<span>
So </span>ΔAOB ≅ ΔCOD [SSS rule] ⇒ x = OH = 16 units.
Answer:
4x / (2x^2+1)
Step-by-step explanation:
g(x)=ln(2x^2+1)
Using u substitution
u= 2x^2 +1
du = 4x dx
g'(x) = d/du ( g(u) du)
We know that the derivative of ln(u) = 1/u since this is always positive
= 1/ u* du
Substituting x back into the equation
g'(x) = 1/(2x^2+1) * 4x
= 4x / (2x^2+1)
In plain and short, what value of "x" makes the expression |3x + 5| to 0?
well, we can check by simply setting it to 0 and solving for x.

notice, all you do is, get the x-value that makes the expression to 0, and then append the constant outside it as the y-value, and that's the vertex.
30 .......... 60%
x ............100%
x = 30*100/60
x = 3000/60
x = 50