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AlekseyPX
3 years ago
7

Which statement is true regarding the functions on the

Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answer:

f(2) = g(2)

General Formulas and Concepts:

<u>Alg I</u>

  • Reading a Cartesian Plane
  • Identifying Coordinates
  • Solutions of systems of equations

Step-by-step explanation:

We see from the graph that f(x) and g(x) intersect at x = 2. Therefore, the point at x = 2 would be equivalent in both graphs/be a solution to both equations.

Therefore, f(2) must equal g(2), as they intersect each other at that point and have the same value of 0.

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Study the function properly

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Which statement is true about the prime polynomial 2x2 + 3x + 3?
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The answer is that it cannot be modeled with a rectangle.
8 0
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Nathan has some overdue library materials. He has a DVD that occurs a fine of one. $15 per day and a book that occurs $0.35 per
Evgen [1.6K]

Answer:

1.15x + 0.35x = 22.50

Step-by-step explanation:

Let x = number of days

If:

  • DVD incurs an overdue fine of $1.15 per day
  • book occurs an overdue fine of $0.35 per day
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8 0
2 years ago
I Need Help Finding The Answer To m
babymother [125]

Answer:

164.4

Step-by-step explanation:

m<ABC = m<ABK + m<KBC

17x + 8 = 42 + 12x - 4

17x - 12x = 42 - 4 + 8 add like terms

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x = 9.2 now replace x with 9.2 in 17x + 8

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3 0
3 years ago
Suppose it is known from large amounts of historical data that X, the number of cars that arrive at a specific intersection duri
Andrew [12]

Answer:

a) P(x>8) = 0.3937

b)  P(x = 2) =0.04661

Step-by-step explanation:

a) From to find the probabilty that in this specific time period, more than 8 cars arrive at the intesection, we use the probability function thus

P(x>8) = 1 - P(x≤8),  Cause you can use the complement for calculate this probability , then:

P(x≤8) = \frac{e^{-6}*6^{0} }{0!}+\frac{e^{-6}*6^{1} }{1!}+\frac{e^{-6}*6^{2} }{2!}+... , until x= 8, then you obtain:

P(x≤8)=0.6063 and

P(x>8) = 1 - P(x≤8)= 1-0.6063 = 0.3937

b) P(x=2)= \frac{e^{-6}*6^{2}  }{2!}

 P(x = 2) =0.04661

3 0
3 years ago
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