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Stells [14]
3 years ago
10

A store allows customers to fill their own bags of candy.Glen decides he only wants caramels and candy corn.caramels sell for $0

.95 per pound, and candy corn sells for $0.79 per pound. Glens bag weighs 1.7 pounds and it costs $1.48.
p is the number of pounds of caramels glen purchases, what expressions could be used to represent the number of pounds candy corn he purchased.

A)1.7
B)1.7-p
C)p+1.7
D)p-1.7
Mathematics
1 answer:
Darya [45]3 years ago
7 0

Answer:


Step-by-step explanation:

Glen decides he only wants caramels and candy corn.  

p is the number of caramels Glen purchases.

Let q be the number of candy corns Glen purchases

Since price per pound caramel is 0.95 cost of caramel

=0.95p

Since price per pound candy corns is 0.79 cost of caramel

=0.79q

Total pounds = Glens bag weight = p+q =1.7

and total cost = 0.95p+0.79q = 1.48

Hence we can write the number of pounds of candy corn in two ways

q = 1.7-p and

q=\frac{1.48-0.95p}{0.79}

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\bold{\huge{\underline{ Solution }}}

<u>We </u><u>have</u><u>, </u>

  • Line segment AB
  • The coordinates of the midpoint of line segment AB is ( -8 , 8 )
  • Coordinates of one of the end point of the line segment is (-2,20)

Let the coordinates of the end point of the line segment AB be ( x1 , y1 ) and (x2 , y2)

<u>Also</u><u>, </u>

Let the coordinates of midpoint of the line segment AB be ( x, y)

<u>We </u><u>know </u><u>that</u><u>, </u>

For finding the midpoints of line segment we use formula :-

\bold{\purple{ M( x,  y) = }}{\bold{\purple{\dfrac{(x1 +x2)}{2}}}}{\bold{\purple{,}}}{\bold{\purple{\dfrac{(y1 + y2)}{2}}}}

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

  • The coordinates of midpoint and one of the end point of line segment AB are ( -8,8) and (-2,-20) .

<u>For </u><u>x </u><u>coordinates </u><u>:</u><u>-</u>

\sf{  -8  = }{\sf{\dfrac{(- 2 +x2)}{2}}}

\sf{2}{\sf{\times{ -8  = - 2 + x2 }}}

\sf{ - 16 = - 2 + x2 }

\sf{ x2 = -16 + 2 }

\bold{ x2 = -14  }

<h3><u>Now</u><u>, </u></h3>

<u>For </u><u>y </u><u>coordinates </u><u>:</u><u>-</u>

\sf{  8  = }{\sf{\dfrac{(- 20 +x2)}{2}}}

\sf{2}{\sf{\times{ 8   = - 20 + x2 }}}

\sf{ 16 = - 20 + x2 }

\sf{ y2 = 16 + 20 }

\bold{ y2 = 36  }

Thus, The coordinates of another end points of line segment AB is ( -14 , 36)

Hence, Option A is correct answer

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