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3 years ago

Of these integers, -65, -42, 65, and 90, which two are farthest apart on the number line?

Mathematics

1 answer:

Hitman42 [59]3 years ago

5 0

The answer is C and its because they are the farthest apart from each other.

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Charactersitics of an algebraic expression

artcher [175]

It would have a variable, and/or coefficients and sometimes constants

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3 years ago

Solve the system: x + 2 = y ,x2 − 10 = y

kondaur [170]

Answer:

If you wanted the intersecting points there is only one and It's (12, 14)

Hope that could help.

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3 years ago

Mandy's square quilt measures 99 in on each edge. how many yd of trim does she need to buy to go around the entire quilt

Masteriza [31]

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3 years ago

Read 2 more answers

Find the value of x. Round to the nearest tenth

VladimirAG [237]

Answer:

36.869 or 36.87

Step-by-step explanation:

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7 0

2 years ago

Emily knows that the area of a rectangle is 54x9y8 square yards and that it’s length 6x3y4 yards. If she divides the area by the

Furkat [3]

Answer:

Width of the rectangle is: $\mathbf{Width= 9x^6 y^4}$

Option C is correct.

Step-by-step explanation:

Area of rectangle = $54x^9y^8$

Length of rectangle = $6x ^ 3y^4$

We need to find width of rectangle.

The formula used is:

$Area\:of\:rectangle=Length\times Width\\Width=\frac{Area\:of\:rectangle}{Length}$

Putting values in the formula to find Width of rectangle

$Width=\frac{Area\:of\:rectangle}{Length}\\Width=\frac{54x^9y^8}{6x^ 3y^4}$

Using the exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

and simplifying the terms we get

$Width=\frac{54x^9y^8}{6x^3y^4}\\Width=9x^{9-3} \: y^{8-4}\\Width=9x^6 y^{4}$

So, Width of the rectangle is: $\mathbf{Width= 9x^6 y^4}$

Option C is correct.

6 0

2 years ago